The answer would be 0.03.
What I did was 50/15 which would get me 0.0333333333333. But since money can only the cents can only have two numbers. So it would be 0.03 as the answer. So it’s the answer d.
Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.


The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
The probability of drawing a green marble is 8/20.
there are 20 marbles total and 8 of them are green.
48. 6 legs x 8 ants = 48 legs.
Given:
Total amount for investment = $32000
Rate of interest for Stock A = 4%
Rate of interest for Stock B = 7%
Jim is hoping to earn $2,000 in interest.
To find:
The amount of investments in Stock A and Stock B.
Step-by-step explanation:
Let amount of investments in Stock A = $x
Amount of investments in Stock B = $y
Total amount for investment = $32000
...(i)
Rate of interests in Stock A and Stock B are 4% and 7%. Total interests is $2000.
...(ii)
From (i) and (ii), we get
Divide both sides by -0.03.
Put x=8000 in (i).
Therefore, the amount of investments in Stock A and Stock B are $8000 and $24000 respectively.