98 Cm should be the answer
Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
12x-30 would be the accurate answer
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
Answer:
50
Step-by-step explanation:
50$ because 20$ is 40%, so times that by 2 which you get 20$ and 80%. Then you divide 20 by 2 then you get 10 which is 20% so you add 10 and you get 50$ which is 100%
