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Fed [463]
3 years ago
8

1 and 2 are examples but I still need help , I don’t understand n this is due today

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

A rational number is a number that can be express as the ratio of two integers. A number that cannot be expressed that way is irrational. ... However, numbers like √2 are irrational because it is impossible to express √2 as a ratio of two integers.

The perfect squares are the squares of the whole numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 … Here are the square roots of all the perfect squares from 1 to 100. 1.

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The equation r=3c +5 represents the values shown in the table below C- 6, 8, 12, 18 R- 23, 29, ?, 59 What is the missing value i
almond37 [142]
The missing value is 53.

3 0
4 years ago
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Difference of two whole numbers is 33 and its ratio is 2:5 then find those<br> numbers.
S_A_V [24]

Answer:

Step-by-step explanation:

Let the two whole numbers be 5x and 2x then

by the question

5x - 2x = 33

3x = 33

x = 33/3

x = 11

Therefore the numbers are

  • 5x = 5*11 = 55
  • 2x = 2*11 = 22

hope it helps:)

8 0
2 years ago
What is the standard form of the equation of the circle?
lisabon 2012 [21]
The standard form of the equation of a circle is:
(x - a) {}^{2}  + (y - b) {}^{2}  = r {}^{2}
Where the point (a,b) represents the centre and r is the radius. So, given your information, the equation will be:
{(x + 4)}^{2}  +  {(y + 3)}^{2}  = 25
4 0
4 years ago
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El número equivalente de 25/50 por favor
Viefleur [7K]

Answer:

El número equivalente de 25/50 es 1/2

Step-by-step explanation:

3 0
2 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
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