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3 years ago

What are the factors of 96

Mathematics

2 answers:

Inessa [10]3 years ago

5 0

I agree with that good luck

MAVERICK [17]3 years ago

4 0

The factors of 96 are 3,5,7

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Find the length of the third side to the nearest tenth. 5 1

adelina 88 [10]

Answer:

square root of 26 (sorry couldn't get the symbol)

Step-by-step explanation:

C^2 = A^2 + B^2 (Pythagoras Theorem)

C^2 = 5^2 + 1^2

C^2 = 26

take square root of both sides

C =

$\sqrt{26}$

3 0

3 years ago

I need help on this question pls

Ivanshal [37]

Answer:

t = 17.5 f = 12

Step-by-step explanation:

If MNOP is a square, you know that each angle is going to be 90°. To solve, let's first set each equation equal to 90°:

$90 = 4t + 20$

and

$90 = 7f + 6$

Then solve both equations:

$90 = 4t + 20 \\ 70 = 4t \\ 17.5 = t$

and

$90 = 7f + 6 \\ 84 = 7f \\ 12 = f$

I hope that helps!

7 0

2 years ago

Cross products question, 3/5 over x multiplied by 12 over 20 what is x

Nitella [24]

Answer:

9/25x

Step-by-step explanation:

3/5/x ×12/20

3/5×1/x ×12/20

36/100x

Divide both by 4

9/25x

The exact value of x cannot be determined because we don't know what the equation is equated to

So we will have to leave the answer as 9/25x

7 0

3 years ago

The teenagers of a school sold 430 tickets for their Christmas program. The girls sold 15% more tickets than the boys sold. How

Paul [167]

The girls sold 230
The boys sold 200

8 0

3 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago