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pashok25 [27]
3 years ago
9

What are the factors of 96

Mathematics
2 answers:
Inessa [10]3 years ago
5 0
I agree with that good luck
MAVERICK [17]3 years ago
4 0
The factors of 96 are 3,5,7
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the morgan famili and the alexander family each ised their sprinkles last summer. the water output was 20. l per hour. The water
erik [133]

Answer:

number of hours  Alexander family ‘s sprinkler work = 20

number of hours  Morgan family ‘s sprinkler work = 30

Step-by-step explanation:

Given in the question,

water output rate for the Alexander family ‘s sprinkler = 40 L  

water output rate for the Morgan family ‘s sprinkler = 20 L

Suppose, number of hours  Alexander family ‘s sprinkler work = x

Suppose, number of hours  Morgan family ‘s sprinkler work = y

Equation1

x + y = 50

Equation 2

40x + 20y = 1400

x = 50 - y

Put this value of x in equation 2

40(50-y) + 20y = 1400

2000 - 40y + 20y = 1400

-20y = 1400 - 2000

-20y = -600

y = 30

Put this value of y in equation 1 to get the value of x

x + 30 = 50

x = 50 - 30

x = 20

 

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3 years ago
12 cubic yards of mulch is 3/4 of a truckload. how much is a full load
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- I have answered this in your last question. (16).
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3 years ago
Add -4 + 2/3<br><br>A) -5 2/3<br><br>B) -4 2/3<br><br>C) -3 2/3<br><br>D) -3 1/3
kodGreya [7K]

Answer:

D

Step-by-step explanation:

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3 years ago
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Elena L [17]
A. f(b) = 3+b

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3 years ago
Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
3 years ago
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