What is equation of the line that is parallel to the line of the y-1=4(x+3) and passes through the the point (4,3)
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A given<u> shape</u> that is <em>bounded</em> by three <u>sides</u> and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of <u>PB</u> is 8.0 units.
A given <em>shape</em> that is <u>bounded</u> by three<em> sides</em> and has got three <em>internal angles</em> is referred to as a <u>triangl</u>e. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the<em> internal angles</em> of any <u>triangle</u> is .
In the given question, point<u> P</u> is <u>center</u> of the given <u>triangle</u> such that <APB = <APC = <BPC = . Such that <u>line</u> PB <em>bisects</em> <ABC into two <u>equal</u> measures of
.
Thus;
<ABP =
Thus,
<ABP + <APB + <BAP =
30 + 120 + <BAP =
<BAP = - 150
<BAP =
Apply the <em>Sine rule</em> to determine the value of PB, such that;
=
=
BP =
= 8
BP = 8.0
Therefore, the value of <u>PB</u> = 8 units.
For more clarifications on Sine rule, visit: brainly.com/question/27174058
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