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kirza4 [7]
3 years ago
10

All points on the circle are the same distance away from the circles ____

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

Centre

Step-by-step explanation:

That distance is radius

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What is the distance between points (1, 4) and (9, 16)? round to the nearest tenth.
11Alexandr11 [23.1K]

Answer:

14.4 to nearest tenth.

Step-by-step explanation:

By the Pythagoras theorem:-

Distance = √ [ (y2-y1)^2 + (x2-x1)^2 ]   where  the 2 points are (x1,y1) and (x2,y2)

= √ [ (16-4)^2 + (9-1)^2]

= √ 208

= 14.4

6 0
3 years ago
Solve for L <br> 10LW=V<br><br> i need help answering this question
vlabodo [156]
10LW=V

L/10W= V/10W

L= V/10W
3 0
3 years ago
What is the solution to the following equation? x2 + 3x + 4 = 0​
andreev551 [17]

Answer:

x=\dfrac{-3\pm \sqrt7i}{2}

Step-by-step explanation:

The given equation is x^{2}+3x+4=0.

We need to find the solution of the above equation.

The solution of an equation ax^2+bx+c=0 is :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

We have, a = 1, b = 3 and c = 4

x=\dfrac{-3+ \sqrt{(3)^2-4(1)(4)} }{2}, \dfrac{-3- \sqrt{(3)^2-4(1)(4)} }{2}\\\\=\dfrac{-3+\sqrt{9-16}}{2}, \dfrac{-3-\sqrt{9-16}}{2}\\\\=\dfrac{-3\pm \sqrt7i}{2}

So, the solution of the given equation is \dfrac{-3\pm \sqrt7i}{2}.

5 0
3 years ago
The 3 is question 3 (it's not apart of the problem). <br>Help Please<br>6th Grade Math
Nat2105 [25]
Area is Base times Height.
the height is 5, and the base is 7 so our equation is
5×7
the answer is 35
8 0
3 years ago
Find the distance between the pair of points and find the midpoint (5,4) and (2,1)
CaHeK987 [17]
Midpoint is (3.5,2.5)
distance is square root of 18

5 0
3 years ago
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