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3 years ago

Write a brief account of Ernest Rutherford’s personal and professional life in no more then 150 words

1 answer:

3 0

i think the answer is that >>>>>Ernest Rutherford was born in rural Spring Grove, on the South Island of New Zealand on August 30, 1871. He was the fourth of 12 children, and the second son. His father, James, had little education and struggled to support the large family on a flax-miller’s income. Ernest’s mother, Martha, worked as a schoolteacher. She believed that knowledge was power, and placed a strong emphasis on her children’s education.As a child, Ernest, whose family called him “Ern,” spent most of his time after school milking cows and helping with other chores on the family farm. Weekends were spent swimming in the creek with his brothers. Since money was tight, Rutherford found inventive ways of overcoming his family’s financial challenges, including birds-nesting to earn funds for his kite-flying supplies. “We haven’t the money, so we’ve got to think,” was Rutherford’s motto at the time.

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Express the pressure 545 mm Hg in kilopascals.

Arlecino [84]

545mm Hg in Kilopascals is 72.6607

I hope this helps you. Good luck stay safe, healthy and, happy!<3

6 0

2 years ago

For the reaction PC15 (8) PC13 (g) + Cl2 (g) K = 0.0454 at 261 °C. If a vessel is filled with these gases such that the initial

Fiesta28 [93]

Answer:

The correct answer is B.

The $K_{eq}$ is samller than $Q$ of the reaction . So,the reaction will shift towards the left i.e. towards the reactant side.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

The expression for $Q$ is written as:

$Q=\frac{[PCl_3][Cl_2]}{[[PCl_5]^1}$

$Q=\frac{0.20 M\times 2.5 M}{0.20 M}$

$Q=2.5$

Given : $K_{eq}$ = 0.0454

Thus as $K_{eq}$ , the reaction will shift towards the left i.e. towards the reactant side.

4 0

3 years ago

Read 2 more answers

Match the element with number of valence electrons

Alla [95]

Answer:

Oxygen-O = 6

Carbon C = 4

Gallium G = 3

Astatine A = 7

Arsenic As = 5

Potassium K = 1

Hydrogen H = 1

Helium H = 2

Explanation:

6 0

2 years ago

Heroin was originally going to be called "wunderlich", a German word for wonderful, since one chemist thought the substance made

Zarrin [17]

Answer:

heroic

Explanation:

Bayer, a German pharmaceutical company, named the substance it synthesized "heroin", probably from the word heroisch, German for heroic, because in field studies people using the medicine felt "heroic".

BTW, I found this information on this wedsite: https://www.answers.com/Q/Where_did_heroin_get_its_name

Also, if you want some more history about this drug, you can visit this article: https://www.narconon.org/drug-information/heroin-history.html

5 0

3 years ago

Hydrocyanic acid, HCN, is a weak acid. (a) Write the chemical equation for the dissociation of HCN in water. (b) Identify the Br

12345 [234]

Answer: a) $HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)$

b) $HCN$ : acid $CN^-$ :conjugate base.

And, $H_2O$ : base $H_3O^+$ : conjugate acid.

c) $HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)$

d) $NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)$

e) $NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)$

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases $H^+$ ions in their aqueous states.

The equation for the dissociation of $HCN$ acid is given by:

$HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)$

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

$HCN$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $CN^-$ which is a conjugate base.

And, $H_2O$ is gaining a proton, thus it is considered as a base and after gaining a proton, it forms $H_3O^+$ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

$HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)$

d) The chemical equation for dissociation of $NaCN$ in water.

$NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)$

e) The chemical equation for the reaction of $NaCN$ and $HCI$

$NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)$

4 0

3 years ago