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Vaselesa [24]
3 years ago
7

With the kinetic energy of a sample increases the____ will also increase

Chemistry
1 answer:
klemol [59]3 years ago
4 0

Answer:

Its Temperature.

Explanation:

  • Kinetic energy is the energy possessed by a body while in motion. Potential energy on the other hand is the energy possessed by a body based on its position.
  • Kinetic energy of a body is determined by the equation; K.E = 3RT/2;
  • From the equation, kinetic energy is directly proportional to the temperature of the system and therefore an increase in the kinetic energy of a sample causes an increase in temperature of the system.
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Cosmology is the study of the grand scale of the universe. You need astronomical observation because then there would be no proof to cosmological theory.
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What is the name of this hydrocarbon
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the IUPAC name of the following compound is 2,3 dimethyl pentane!

5 0
3 years ago
1) A car is traveling down the interstate at 37.1 m/s. The driver sees a cop and quickly slows down. If the driver slows to 29.8
WITCHER [35]

1)

The acceleration of the car is the rate of change of velocity of the car; it can be calculated as:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity of the car to change from u to v

In this problem, for this car we have:

u = 37.1 m/s

v = 29.8 m/s

t = 3 s

So, the acceleration is:

a=\frac{29.8-37.1}{3}=-2.43 m/s^2

2)

The work done in lifting the box is equal to the potential energy transferred to the box during the process; it is given by:

W=Fd

where

F is the force applied

d is the displacement of the box

Here we have:

F = 87.3 N is the force applied

d = 2.04 m is the displacement of the box

So, the work done to lift the box is:

W=(87.3)(2.04)=178.1 J

3)

The power is the rate of work done per unit time. It is calculated as:

P=\frac{W}{t}

where

W is the work done

t is the time taken to do the work

For the child in this problem, we have:

W = 1250 J is the work done by the child running up the stairs

P = 267 W is the power used

Therefore, re-arranging the equation, we find the time taken:

t=\frac{W}{P}=\frac{1250}{267}=4.68 s

4)

The kinetic energy of an object is the energy possessed by the object due to its motion. Mathematically, it is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the rabbit in this problem, we have:

m = 8.642 kg is the mass of the rabbit

KE = 125.6 is its kinetic energy

Solving the formula for v, we find the speed of the rabbit:

v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2(125.6)}{8.642}}=5.4 m/s

5)

The efficiency of a machine is the ratio between the energy produced in output by the machine and the work done in input. Mathematically, it is given by

\eta = \frac{E_{out}}{W_{in}}\cdot 100

where

E_{out} is the energy in output

W_{in} is the work in input

For the machine in this problem,

W_{in}=120 J is the work in input

E_{out}=93 J is the energy in output

Therefore, the efficiency of this machine is:

\eta=\frac{93}{120}\cdot 100=77.5\%

6)

During a collision, the total momentum of the system is always conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 =(m_1+m_2)v

where

m_1=212 kg is the mass of the first car

u_1=8.00 m/s is the initial velocity of the first car

m_2=196 kg is the mass of the 2nd car

u_2=6.75 m/s is the initial velocity of the 2nd car

v is the final velocity of the two cars stuck together (after the collision, they move together)

Solving the equation for v, we find:

v=\frac{m_1 u_1 +m_2 u_2}{m_1 +m_2}=\frac{(212)(8.00)+(196)(6.75)}{212+196}=7.40 m/s

7)

The relationship between speed, frequency and wavelength of a wave is given by the wave equation:

v=f\lambda

where

v is the speed of the wave

f is the frequency of the wave

\lambda is the wavelength

For the wave in the string in this problem we have:

\lambda=0.23 m (wavelength)

f = 12 Hz (frequency)

So, the speed of the wave is:

v=(12)(0.23)=2.76 m/s

8)

The relationship between frequency and wavelength for an electromagnetic wave is given by

c=f\lambda

where:

c is the speed of light in a vacuum

f is the frequency of the wave

\lambda is the wavelength of the wave

For the blue light in this problem, we have

f=6.2\cdot 10^{14}Hz (frequency)

while the speed of light is

c=3.0\cdot 10^8 m/s

So, the wavelength of blue light is:

\lambda=\frac{c}{f}=\frac{3.0\cdot 10^8}{6.2\cdot 10^{14}}=4.8\cdot 10^{-7} m

9)

The sound wave in this problem travels with uniform motion (=constant velocity), therefore we can use the following equation:

d=vt

where

d is the distance covered by the wave

v is the speed of the wave

t is the time elapsed

In this problem:

v = 343 m/s is the speed of the sound wave

t = 0.287 s is the time elapsed

So, the distance covered by the wave is

d=(343)(0.287)=98.4 m

3 0
3 years ago
Which of the following is smaller than the atomic radius of beryllium? a. the ionic radius of beryllium b. the atomic radius of
slamgirl [31]
The best quality answer I would say that it is cC
6 0
3 years ago
What is the molarity of a hydrochloric acid solution, when 30.0 mL is neutralized by 48.0 mL of 0.100 mol/L
bulgar [2K]

The molarity of a hydrochloric acid solution : 0.32 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution).

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.  

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  

1 ⇒HCl (valence=1, HCl ⇒H⁺+Cl⁻, one H⁺)

2⇒Ca(OH)₂(valence=2, Ca(OH)₂⇒Ca²⁺+2OH⁻, two OH⁻)

M₂=0.1 M

V₂=48 ml=0.048 L

V₁=30 ml=0.03 L

\tt M_1.V_1.n_1=M_2.V_2.n_2\\\\M_1\times 0.03\times 1=0.1\times 0.048\times 2\\\\M_1=0.32

3 0
3 years ago
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