Answer:
about 65 days
Step-by-step explanation:
46/30 = 1.53 pounds per day
100/1.53 = about 65
Consider such events:
A - slip with number 3 is chosen;
B - the sum of numbers is 4.
You have to count ![Pr(A|B).](https://tex.z-dn.net/?f=Pr%28A%7CB%29.)
Use formula for conditional probability:
![Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.](https://tex.z-dn.net/?f=Pr%28A%7CB%29%3D%5Cdfrac%7BPr%28A%5Ccap%20B%29%7D%7BPr%28B%29%7D.)
1. The event
consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event
is
![Pr(A\cap B)=\dfrac{1}{20}.](https://tex.z-dn.net/?f=Pr%28A%5Ccap%20B%29%3D%5Cdfrac%7B1%7D%7B20%7D.)
2. The event
consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event
is
![Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.](https://tex.z-dn.net/?f=Pr%28B%29%3D%5Cdfrac%7B2%7D%7B20%7D%3D%5Cdfrac%7B1%7D%7B10%7D.)
3. Then
![Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.](https://tex.z-dn.net/?f=Pr%28A%7CB%29%3D%5Cdfrac%7B%5Cfrac%7B1%7D%7B20%7D%20%7D%7B%5Cfrac%7B1%7D%7B10%7D%20%7D%3D%5Cdfrac%7B1%7D%7B2%7D.)
Answer: ![\dfrac{1}{2}.](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D.)
A linear equation has 1 for all exponents on the placeholders
aka the equation is first degree (aka the hightest exponent on placeholders=1) so
it is linear
Answer:
RP: x equals 0
JH: x equals -11
EG: x equals 9
The correct answer is 5 1/2 because if it weren’t simplified it would be 6/2 which makes the numerator the greatest.