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Maksim231197 [3]
3 years ago
5

Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0
It is 245m thank me later
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When you apply for a scholarship, you may have to write an application essay?
Anna [14]

Answer your answer is b

Step-by-step explanation:

to show that you have the writing skills in order to succeed in college

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If the diameter of circle O is 20 and CE = 4, then determine the length of AB. Show how you arrived at your answer.
Aneli [31]

Answer:  Length of AB is 16 cm

Step-by-step explanation:

Given: Diameter of a circle is 20 cm and CE = 4 cm

Now as shown in figure AO, BO, CO are radii

\text { Radius } =\dfrac{\text {Diameter}}{2} = \dfrac{20}{2} = 10 cm

Therefore

AO=BO=CO= 10 cm

Now

OE = CO- CE  \Rightarrow OE= 10 -4 = 6 cm

Now in Δ OEB

∠OEB =90°

Therefore by Pythagoras theorem : In a right angle triangle the square of hypotenuse is equal to the sum of square of other two sides.

So we have

BO^2=BE^2+EO^2\\\\\Rightarrow 10^2= BE^2 +6^2\\\\\Rightarrow BE^2= 100-36\\\\\Rightarrow BE^2 = 64 \\\\\Rightarrow BE= 8 cm

Now as we know perpendicular to the chord from the center of a circle bisect the chord.

Therefore

AB= 2\times BE = 2\times 8=16 cm

Hence , the  length of AB is 16 cm .

8 0
3 years ago
Order the fractions from least to greatest. A)− 8/3 , − 5/2 , − 7/ 4 , − 3/ 5 B) − 3/ 5 , − 5/2 , − 7/4 , − 8/3 C) − 8/3 , − 5/2
Olenka [21]

Answer:

A)− 8/3 , − 5/2 , − 7/ 4 , − 3/ 5

Step-by-step explanation:

8 0
3 years ago
Which number is the best estimate for point F?
andreev551 [17]

Answer:

e

Step-by-step explanation:

you can use this phrase to help u

5 or above give it a shove

4 or below let it go

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Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030
Alex777 [14]
F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025
8 0
2 years ago
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