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lbvjy [14]
3 years ago
14

Do the question in the picture and then tell how you got your answer

Mathematics
1 answer:
liraira [26]3 years ago
7 0
2(2\sqrt4)^{-2}=\\
2\cdot(2\cdot2)^{-2}=\\
2\cdot(2^2)^{-2}=\\
2\cdot2^{-4}=\\
2^{-3}=\\
\frac{1}{8}

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Write the first 4 terms of the arithmetic sequence With first term 37 and common difference 9
alexandr402 [8]

Answers:

first term = 37

second term = 46

third term = 55

fourth term = 64

==========================================

Explanation:

Start at 37. Add 9 to this term to get the second term. Add 9 to that result to get the next term, and so on.

first term = 37

second term = 37+9 = 46

third term = 46+9 = 55

fourth term = 55+9 = 64

-----------

The nth term formula is

a(n) = 9n+28

It can be found by plugging a = 37 and d = 9 into the general form

a(n) = a + d*(n-1)

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