Answer: multiply x by 2 in the first equation and subtract the second equation
Step-by-step explanation:
To solve a system of linear equations by elimination method , our first step is to make its (either x or y) coefficient same.
For that we multiply a number to both sides of the equation not to only one term.
So by checking all the given options it is pretty clear that the last option is not applicable for elimination method because in this 2 is multiplied to only one term, which proceeds to loose the balance of the equation.
Thus , an INCORRECT step that will NOT produce a system with the same solution is "multiply x by 2 in the first equation and subtract the second equation
".
Let's say the side length of square A is x, which means the side length of square B is 2x.
Then, the area of square A can be written as , and the area of square B can be written as .
There's no diagram here with shaded region, so I'll just find the area of square A as a percentage of the area of square B:
= 1/4 = 25%
So, the answer is 25% (note this is the answer to the question: "express the area of square A as a percentage of the area of square B; there is no diagram showing me where the shaded area is, so I cannot answer the original question
Answer:
The ratio of the amount for swordfish to the amount of salmon is 6:4
Step-by-step explanation:
Given as :
The price for 1 pound of swordfish = The price of 1.5 pound of salmon
So, On this relation
The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon
i.e The price for 2 pound of swordfish = The price of 3 pound of salmon
Now According to question
Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39
Let the money she pay for swordfish = 2 sw
And The money she pay for salmon = 3 sa
∵, The total money she pay for both = $ 39
I.e 2 sw + 3 sa = 39
As 2 sw = 3 sa
So, 3 sa + 3 sa = 39
Or, 6 sa = 39
or, sa = 
= 
∴ sw = × 
or, sw = 
Now, the ratio of the amount for swordfish to the amount of salmon = 
I.e The ratio = 
Hence The ratio of the amount for swordfish to the amount of salmon is 6:4
Answer
86+08p because both have the answer
