2 years ago

There Are TWO answers to this . I will reward brainliest

1 answer:

5 0

The answer should be the first option and the third. A convenience sample is very similar to a biased sample.

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tatuchka [14]

Answer:

-2

Step-by-step explanation:

6 0

3 years ago

NeX [460]

B

Hope this helps :)

Can I have Brainliest please

5 0

3 years ago

Oksi-84 [34.3K]

Your answer should be -6

6 0

3 years ago

Korolek [52]

There are multiple solutions and they will vary.

Hope this helps!
Can u plz mark me as brainliest? I really need it!

5 0

2 years ago

Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of $\$800 \times 1.07^t$ .

We want the find the number of years n such that

$\$856 \times 1.07^n = \$1400$

Solve for n :

$856 \times 1.07 ^n = 1400$

$1.07^n = \dfrac74$

$\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)$

$n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)$

$n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}$

4 0

1 year ago