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3 years ago

Which number(s) below belong to the solution set of the inequality? 11x > 32 (Check all that apply)

Mathematics

1 answer:

morpeh [17]3 years ago

6 0

For this case we have the following inequality:
$11x\ \textgreater \ 32
$
From here, we must clear the value of x.
We have then:
$x\ \textgreater \ \frac{32}{11} 
$
$x\ \textgreater \ 2.9
$
Therefore, the solution set is all the numbers belonging to the following interval:
(2.9,∞)
Note: see attached image for graphic solution.
Answer:
The numbers that belong to the solution of the inequality are those that are shown in the attached graph and that belong to the interval:
(2.9,∞)

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Factor the polynomial. <br> 25 – x²

katovenus [111]

Answer:

(5 + x)(5 - x)

Step-by-step explanation:

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The length of a rectangle is 4 more than its width. The area of the rectangle is 21m2 . What is the measure of the width?

iris [78.8K]

Length(l)= 4+ w
Width(w)=w
Area(A)= 21m^2

so keep in mind Area= Length × width

A= l×w
21=(4+w)(w)
21= 4w+ 2w
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The width is 3.5m

so the answer is about 4m

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Darren wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment in which he yawn

denis23 [38]

Answer:

10.5 minutes

Step-by-step explanation:

Thinking about the problem

The modeling function is of the form P(t)=A⋅Bf(t), where B=4B=4B, equals, 4 and f(t)=\dfrac{t}{10.5}f(t)=

10.5

f, left parenthesis, t, right parenthesis, equals, start fraction, t, divided by, 10, point, 5, end fraction.

Note that each time f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111, the quantity is multiplied by B=4B=4B, equals, 4.

Therefore, we need to find the ttt-interval over which f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111.

Hint #22 / 3

Finding the appropriate unit interval

fff is a linear function whose slope is \dfrac{1}{10.5}

10.5

start fraction, 1, divided by, 10, point, 5, end fraction.

This means that whenever ttt increases by \Delta tΔtdelta, t, f(t)f(t)f, left parenthesis, t, right parenthesis increases by \dfrac{\Delta t}{10.5}

10.5

Δt

start fraction, delta, t, divided by, 10, point, 5, end fraction.

Therefore, for f(t)f(t)f, left parenthesis, t, right parenthesis to increase by 111, we need \Delta t=10.5Δt=10.5delta, t, equals, 10, point, 5. In other words, the ttt-interval we are looking for is 10.510.510, point, 5 minutes.

Hint #33 / 3

Summary

The number of people who yawned quadruples every 10.510.510, point, 5 minutes.

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3 years ago

The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot

Katarina [22]

Answer:

$(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

$(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

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Norma-Jean [14]

Answer:

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