How to find the product of (3y^2+ 2y + 2)(3y^2- 4y - 5)

Mathematics

1 answer:

Nastasia [14]3 years ago

3 0

Answer:

= 9y^4 -6y^3 -17y^2 -18y -10

Step-by-step explanation:

(3y^2 + 2y + 2) x (3y^2 – 4y – 5)

9y^4 - 12y^3 - 15y^2 + 6y^3 -8y^2 -10y +6y^2 -8y -10

= 9y^4 -6y^3 -17y^2 -18y -10

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