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4 years ago

How to find the product of (3y^2+ 2y + 2)(3y^2- 4y - 5)

Mathematics

1 answer:

Nastasia [14]4 years ago

3 0

Answer:

= 9y^4 -6y^3 -17y^2 -18y -10

Step-by-step explanation:

(3y^2 + 2y + 2) x (3y^2 – 4y – 5)

9y^4 - 12y^3 - 15y^2 + 6y^3 -8y^2 -10y +6y^2 -8y -10

= 9y^4 -6y^3 -17y^2 -18y -10

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Shanti is taking a cube-shaped gift to a friend's birthday party. She wants to wrap it but she doesn't have very much paper, so

Marrrta [24]

Answer:

It will take Shanti 150 square inches of paper to wrap the gifts

Step-by-step explanation:

Shanti wraps the gift she is taking to a friend's birthday party. She doesn't have very much paper, so she does not overlap any of the edges. The side lengths of the cube are all 5in.

How much paper did it take to cover the gift?

Solution

To solve this, you will find the surface area of a cube

Surface area of a cube = 6a^2

Where,

a=side length of the cube

a= 5 in

a^2=a × a

=5 × 5

=25 in^2

a^2=25 in^2

Surface area of a cube = 6a^2

=6 × 25 in^2

=150 in^2

It will take Shanti 150 square inches of paper to wrap the gifts

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3 years ago

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Name the following<br> transformations

Elden [556K]

Answer:

reflection, rotation, and translation.

3 0

3 years ago

I need help with this please.

user100 [1]

Answer:

the slope is 60

Step-by-step explanation:

the slope is the number multiplying the x value, or t in this case.

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3 years ago

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From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

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3 years ago

The football team has a total of 50 jerseys. There are 10 medium-sized jerseys. What percent of the jerseys are medium-sized j

mrs_skeptik [129]

Answer:

it is 20% your welcome

Step-by-step explanation:

because when you divide 100 by 2 its 50 so its 20%

5 0

3 years ago

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