How to find the product of (3y^2+ 2y + 2)(3y^2- 4y - 5)
1 answer:
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Quadratic Formula: (-b +/- sqrt(b^2 - 4ac)) / 2a
2x^2 - 3x = 12
2x^2 - 3x - 12 = 0
a = 2
b = -3
c = -12
(--3 +/- sqrt( (-3)^2 - 4(2)(-12) )) / 2(2)
3 +/- sqrt( 9 + 96 ) / 4
3 +/- sqrt(105) / 4
Answers: ,
Hope this helps!
Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:
Horizontal asymptote at y = 0.
<h3>What are the horizontal asymptotes of a function?</h3>They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.
Researching this problem on the internet, the functions are given as follows:
.
The limits are given as follows:
Hence, the correct statement is:
Horizontal asymptote at y = 0.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
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