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3 years ago

A = , b = , c = HELP ASAP!WILL MARK BRAINLIEST AND WORTH 23 POINTS!

Mathematics

2 answers:

balu736 [363]3 years ago

6 0

Answer:

a = 2

b = 3

c = 2³ or 8

Step-by-step explanation:

Exponent Rule: $\frac{b^m}{b^n} =b^{m-n}$

log₂(4) = 2 or 2² = 4

2⁵/2² = 2³

2³ = 8

Lena [83]3 years ago

5 0

Answer:

a=2

b=3

c=8

Step-by-step explanation:

a=2, 2^a must equal 4

b=3, 2^b must equal 8 which is answer to 2⁵/4

c=8, the answer to 2⁵/4, and

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How do you write 6n + 8n + 4as a product of 2 factors?

Alla [95]

14n+ 4 = 2( 7n + 2 ) ; the factors are 2 and ( 7n + 2 ) ;

8 0

3 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

Plz answer these 2 i really need help I'm not all that smart

kati45 [8]

Answer: 141.7 cm3

Explanation: you multiple 6.1, 6.7, 10.4 then divide by 3 which equals 141.68. Round it and we’re left with 141.7 cm3.

8 0

3 years ago

Read 2 more answers

Help me ASAP it’s a math test

expeople1 [14]

Answer:

I would say the last one, bc b Is negative correct?

4 0

3 years ago

H(t)= (t+3)^2 + 5

oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

$\frac{h(-1)-h(-5)}{-1+5}$

so we find:

$h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9$

then the average rate of change becomes:

$\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0$

5 0

3 years ago