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puteri [66]
3 years ago
9

Venus is about 10 to the 8th power kilometers from the Sun. Saturn is about 10 to the 9th power kilometers from the Sun. About h

ow many times farther from the Sun is Saturn than Venus?
Mathematics
1 answer:
Contact [7]3 years ago
4 0
Saturn is 10 times farther from the sun than Venus 
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Two cars are traveling in the same direction. The first car is going 40 mi/h and the second car is going 55 mi/h. The first car
dexar [7]

Answer:

The equation you are asking for is

40*(t+3) = 55*t,

where t is the time counted after the second car started.

The equation says that the distance covered by each car from the starting point to the catching point is the same for both cars.

Step-by-step explanation:

7 0
3 years ago
(1) a sample of 36 ball have been randomly pull out of jar. it contained 16 red balls. what is the probability of that happening
Lynna [10]
There is a .41025...% chance of that happening. moving on the jar is not 25% filled with red balls because 25% of 36 is only 9 and he pulled out 16 red balls hence forth that is impossible if the jar is only 25% red balls 

hope this helped!!!
4 0
3 years ago
Which transformation have been preformed on a graph of f(x)=x2 to obtained the graph of g(x) =-3(x+1)2-4?
avanturin [10]

Horizontal shift because g(x)=f(x+1) 1 unit left

Vertical shift because g(x)=f(x+1)-4 4 units down

Reflected across x-axis because g(x)=-f(x)

Vertically stretched because g(x)=3(f(x))

Step-by-step explanation:

We need to identify which transformation have been preformed on a graph of f(x)=x2 to obtained the graph of g(x) =-3(x+1)2-4?

Rules for transformation:

Horizontal shift: depends on the value h

if g(x)=f(x+h) then: the graph is shifted left h units

if g(x)=f(x-h) then: the graph is shifted right h units

Vertical Shift: depends on the value k

if g(x)=f(x)+k then: the graph is shifted up k units

if g(x)=f(x)-k then: the graph is shifted down k units

Reflection:

if g(x)=-f(x) then graph is reflected at x-axis

if g(x)=f(-x) then graph is reflected at y-axis

Vertical Stretch:

if g(x)=c.f(x) then graph is vertically stretched.

In the given question:

f(x)= x^2

g(x)=-3(x+1)^2-4

Applying the above rules of transformation:

The graph is:

Horizontal shift because g(x)=f(x+1) 1 unit left

Vertical shift because g(x)=f(x+1)-4 4 units down

Reflected across x-axis because g(x)=-f(x)

Vertically stretched because g(x)=3(f(x))

Keywords: Transformations

Learn more about Transformations at:

  • brainly.com/question/2415963
  • brainly.com/question/3779181
  • brainly.com/question/5563823
  • brainly.com/question/9381523

#learnwithBrainly

7 0
3 years ago
Using the graph below, what is the value of f(6) ?
Dima020 [189]

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f(6) =   - 2

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

5 0
3 years ago
Read 2 more answers
Use the binomial expansion and approximation to find √3​
belka [17]

According to the use of binomial expansion, the approximate value of √3 is found by applying the infinite sum √3 = 1 + (1 /2) · 2 - (1 / 8) · 2² + (1 / 16) · 2³ - (5 / 128) · 2⁴ + (7 / 256) · 2⁵ - (21 / 1024) · 2⁶ + (33 / 2048) · 2⁷ - (429 / 32768) · 2⁸ +...

An acceptable result cannot be found manually for it requires a <em>high</em> number of elements, with the help of a solver we find that the <em>approximate</em> value of √3 is 1.732.  

<h3>How to approximate the value of a irrational number by binomial theorem</h3>

Binomial theorem offers a formula to find the <em>analytical</em> form of the power of a binomial of the form (a + b)ⁿ:

(a + b)^{n} = \sum \limits_{k = 0}^{n} \left(\begin{array}{c}n\\k\end{array}\right)\cdot a^{n-k} \cdot b^{k}     (1)

Where:

  • a, b - Constants of the binomial.
  • n - Grade of the power binomial.
  • k - Index of the k-th element of the power binomial.

If we know that a = 1, b = 2 and n = 1 / 2, then an approximate expression for the square root is:

√3 = 1 + (1 /2) · 2 - (1 / 8) · 2² + (1 / 16) · 2³ - (5 / 128) · 2⁴ + (7 / 256) · 2⁵ - (21 / 1024) · 2⁶ + (33 / 2048) · 2⁷ - (429 / 32768) · 2⁸ +...

To learn more on binomial expansions: brainly.com/question/12249986

#SPJ1

8 0
2 years ago
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