Answer:
We need the events to be able to put them in order. :\
Explanation:
Answer:
When the pKa is 6.0, we can determine the fraction of protonated H is by:
pH = pKa + log [A]/[HA]
Where
A = Deprotonated imidazole side
HA = Protonated side
Given, pH = 5.0
5 = 6 + log [A]/[HA]
log [A]/[HA] = -1 (take antilog of both side)
[A]/[HA] = 0.1
The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 0.1
Given, pH = 7.5
7.5 = 6 + log [A]/[HA]
log [A]/[HA] = 1.5 (take antilog of both sides)
[A]/[HA] = 31.62
The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 31.62
Answer:
1,897,087=1,900,207.2=3,120 (the equasion you gave when distributed)
Answer to the question(Money made): ($)3,372
Explanation:
solved it out by multiplying
<span> One pair of sex chromosomes and 22 pairs of autosomes
that should be right. please let me know if it is
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