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ella [17]
3 years ago
6

Which represents a quadratic function ?

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

Answer:

\boxed{\boxed{B.\ f(x)=\dfrac{3}{4}x^2+2x-5}}

Step-by-step explanation:

Quadratic function-

It is a function that can be represented by an equation of the form f = ax^2 + bx + c, where a\neq 0

In a quadratic function, the greatest power of the variable is 2.

As in the first option the highest power is 3, so it is not a quadratic function.

Even though the power of x is 2 in the third option, but as it is in the denominator, so the overall power of x becomes -2. Hence it is not a quadratic function.

As the coefficient of x^2 is 0 in case of fourth option, so it is not a quadratic function.

Equation in option 2 satisfies all the conditions of quadratic function, hence it is the quadratic function.

zepelin [54]3 years ago
7 0

Answer:

b

Step-by-step explanation:

lol dude answered it already

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Tju [1.3M]

<span>Formula: H(t) = 56t – 16t^2   </span>

H(t) = - 16t^2 + 56t

<span><span>A.      </span>What is the height of the ball after 1 second? H (1) = 56(1) – 16(1) ^2 = 40 pt.</span>

<span><span>B.      </span>What is the maximum height? X = - (56)/2(- 16) = 1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>

<span><span>C.      </span><span>After how many seconds will it return to the ground? – 16t^2 + 56t = 0   - 8t =0 t = 0</span></span>

<span><span>-          </span><span>8t (2 + - 7) = 0     2t – 7 = 0  t = 7/2   Ans: 3.5 seconds</span></span>

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3 years ago
In triangle opq right angled at p op=7cm,oq-pq=1 determine the values of sinq and cosq
soldi70 [24.7K]

Answer:

see explanation

Step-by-step explanation:

let pq = x

given oq - pq = 1 then oq = 1 + x

Using Pythagoras' identity, then

(oq)² = 7² + x²

(1 + x)² = 49 + x² ( expand left side )

1 + 2x + x² = 49 + x² ( subtract 1 from both sides )

2x + x² = 48 + x² ( subtract x² from both sides )

2x = 48 ( divide both sides by 2 )

x = 24 ⇒ pq = 24

and oq = 1 + x = 1 + 24 = 25 ← hypotenuse

sinq = \frac{opposite}{hypotenuse} = \frac{7}{25}

cosq = \frac{adjacent}{hypotenuse} = \frac{24}{25}



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Answer:

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Step-by-step explanation:

227.5+97.5=325

325/65=5

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