All categories

4 years ago

Bella bought packs of stickers to give to her friends. Each pack cost $4. She spent a total of

Mathematics

1 answer:

Shalnov [3]4 years ago

4 0

Answer:

8 packs

Step-by-step explanation:

$4 = 1 pack

$32 = ?

$32 = $32/$4

$32 = 8 packs

You might be interested in

What is 0.85 rounded

Nikolay [14]

0.85 is 0.85 rounded to the nearest hundredth.
.9 is 0.85 rounded to the nearest tenth
1 is 0.85 rounded to the nearest whole number
0 is 0.85 rounded to the nearest ten, hundred, etc.

7 0

4 years ago

Read 2 more answers

A student spends no more than 2 hours on his math and english homework. If math takes about twice as long as english, what is th

SSSSS [86.1K]

Answer:

it would take him 40 mins

Step-by-step explanation:

6 0

3 years ago

Write in the measure, in degrees, for each angle marked with a question mark.

garik1379 [7]

1. 180－146＝34°

2. 40° (alternate angles are equal)

3. 50° (vertically opposite angles are equal)

4. 180－75＝105° (co-interior angles add up to 180°)

5. 90－65＝25°

Hope my answer helped u :)

3 0

3 years ago

A figure with 6 edges. How many edges does this figure have? It has edges.

Anestetic [448]

Hexagon has six edges. The figure you're trying to figure out is hexagon I guess.

3 0

3 years ago

Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar

yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

Let $\mu_1$ = true mean number of sales at location A.

$\mu_2$ = true mean number of sales at location B

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1 \geq \mu_2$ {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1< \mu_2$ {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1_-_n__2-2$

where, $\bar X_1$ = sample average of items sold at location A = 39

$\bar X_2$ = sample average of items sold at location B = 49

$s_1$ = sample standard deviation of items sold at location A = 8

$s_2$ = sample standard deviation of items sold at location B = 4

$n_1$ = sample of days location A was observed = 18

$n_2$ = sample of days location B was observed = 13

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2} }{18+13-2} }$ = 6.64

So, test statistics = $\frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13} } }$ ~ $t_2_9$

= -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

3 0

3 years ago