The answer would be A. 50 check the pdf for work.
A normal space<span> is a </span>topological space X<span> that satisfies </span><span>Axiom T4</span><span>: every two disjoint </span>closed sets<span> of </span>X<span> have disjoint </span>open neighborhoods<span>.</span>
Answer: The blue whale's weight is 150 times heavier than the narwhal's weight.
Step-by-step explanation:
Given: Weight of Blue whale = 
Weight of Narwhal = 
Number of times blue whale's weight is heavier than the narwhal's weight = 
![=\dfrac{3\times10^5}{2\times10^3}\\\\=1.5\times10^{5-3}\ \ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=1.5\times10^2\\\\=1.5\times100=150](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B3%5Ctimes10%5E5%7D%7B2%5Ctimes10%5E3%7D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E%7B5-3%7D%5C%20%5C%20%5C%20%5B%5Cdfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E2%5C%5C%5C%5C%3D1.5%5Ctimes100%3D150)
Hence, the blue whale's weight is 150 times heavier than the narwhal's weight.
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Answer:
6682.5cm
Step-by-step explanation:
29+6.5=35.5+19=54.5+1,726=1,780.5+1121=2901.5+2671=5572.5+1110=6682.5
