5, because it is halfway between 0 and 10.
Answer: P(B|G) = 3/5 = 0.6
the probability that the guest is the friend of bride, P(bride | groom) is 0.6
Complete Question:
The usher at a wedding asked each of the 80 guests whether they werea friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Given that the randomly chosen guest is the friend of groom, what is the probability that the guest is the friend of bride, P (bride | groom)
Step-by-step explanation:
The conditional probability P(B|G), which is the probability that a guest selected at random who is a friend of the groom is a friend of the bride can be written as;
P(B|G) = P(B∩G)/P(G)
P(G) the probability that a guest selected at random is a friend of the groom.
P(G) = number of groom's friends/total number of guests sample
P(G) = 50/80
P(B∩G) = the probability that a guest selected at random is a friend is a friend of both the bride and the groom.
P(B∩G) = number of guests that are friends of both/total number of sample guest
P(B∩G) = 30/80
Therefore,
P(B|G) = (30/80)/(50/80) = 30/50
P(B|G) = 3/5 = 0.6
I'm not all that sure but hopefully this is right...
x=20+0.08x
Answer:sedan can hold 3 people and a minivan can hold 9 people.
Step-by-step explanation:
Suppose the number of passengers each sedan can carry is A and the number of passengers each minivan can carry is B
So 3A + 2B = 21 and 3A + 3B = 27
If we subtract the equations we can solve for B
3A + 3B = 27
-3A - 2B = 21
___________
B = 6
Now we know Each minivan can hold 6 passengers and we can solve for A.
3A + 3B = 27
3A + 3(6) = 27
3A + 18 = 27
- 18. -18
__________
3A = 9
A =3
You can check this by solving the other equation.
3A + 2B = 21
3(3) + 2(6) = 21
9 + 12 = 21
Hope that helps
The proper equation would b y=3x / 2
