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Fed [463]
3 years ago
12

Which is an x-intercept of the graph of the function y=cot(3x)

Mathematics
1 answer:
AveGali [126]3 years ago
5 0

Answer:

x-intercept of the graph of the function y = \cot(3x) is, (\frac{\pi}{6} \pm \frac{n\pi}{3} , 0)

Step-by-step explanation:

Given the function: y = \cot(3x)                        ......[1]

x-intercept defined as the graph crosses the x-axis.

Substitute value of y = 0 in [1] and solve for x;

0 = \cot(3x) or

\cot(3x) = 0

Take the inverse cotangent of both sides of the equation and solve for x;

3x = arccot (0)

We know the exact value of arc\cot(0) = \frac{\pi}{2}

then;

3x = \frac{\pi}{2}

Divide both sides by 3 we get;

x = \frac{\pi}{6}

Since, the cotangent function is positive in the first and third quadrants.

The period of the function \cot(3x) is \frac{\pi}{3} so values will repeat every \frac{\pi}{3}  radians in both directions.

we have;

x =\frac{\pi}{6} \pm \frac{n\pi}{3}

Therefore, the x-intercept of the graph of the function y = \cot(3x)  is ;

(\frac{\pi}{6} \pm \frac{n\pi}{3} , 0)  for every integer n;




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mr_godi [17]

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(12,10)

Step-by-step explanation:

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3 years ago
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n200080 [17]

Answer:

y-intercept = -4

Step-by-step explanation:

equation of a line: y=mx+b

two points given are (5, -6.5) and (-12, 2)

first we can easily find value of m or the slope, by using the slope formula. the value of m=-0.5.

formua to find m: \frac{2-(-6.5)}{-12-5}= -0.5

to find the value of b (the y-intercept), we need to plug in a y and x value, we are given 2 ordered pairs, you can use either one and plug x-value in for x and the y-value in for y.

if i plug in (5, -6.5), my equation looks like this: -6.5=5(-0.5)+b

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4 0
3 years ago
Halle la ecuación del eje x y la ecuación del eje y, usando dos puntos que se encuentren sobre los mismos.
lisov135 [29]

Una linea recta ( cualquier eje coordenado es una línea recta) queda definida si se conocen dos puntos que están sobre ella.

Solución:

Ecuación del eje x      y = 0

Ecuación del eje y      x = 0

Para darle respuesta a la pregunta podemos seguir el siguiente procedimiento:

  • Escogemos dos puntos arbitrarios sobre el eje x, por ejemplo

P ( 2 ; 0 )  y Q ( 5 ; 0 )         ( todos los puntos sobre el eje x tienen coordenada y = 0.

Según la cual  m = (y₂ - y₁)/ ( x₂ - x₁ )    m = 0

  • Usamos la ecuación pendiente-Intercepto

y = m×x + b         donde m es la pendiente y b el intercepto con el eje y

y entonces tenemos:

  • m = 0    b ( 0 ; 0 )
  • Por sustitución en la ecuación pendiente-intercepto

y = 0

Procediendo de forma similar obtendremos la ecuación del eje y

P´( 0 ; 4 )     Q´( 0 : 8 ) entonces

y = m×x + b

En este caso, la pendiente no es definida ( tang 90° ) y b es de nuevo el punto b ( 0 ; 0).

A partir de  que todos y cada uno de los puntos sobre el eje y son  de valor 0 para x, concluímos que  ecuación del eje y es

x = 0

Enlaces de interés:brainly.com/question/21135669?

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I don't know which of those answers you are looking for. 
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