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Citrus2011 [14]
3 years ago
10

Why is it necessary to round your answer in part (a) to the nearest integer?

Mathematics
1 answer:
svetlana [45]3 years ago
7 0
Can you tell me what the question for part a is?
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Celik, S. (2011). A media comparison study on first aid instruction. Health Education Journal. 72(1), 95-101
aniked [119]

Answer:

The answer is "Option a".

Step-by-step explanation:

In the given scenario, The appropriate test for the teaching profession's accomplishment pre and post-class would be the two-sample t-test with dependent samples, that's why choice "a" is correct.

7 0
3 years ago
The largest number that rounds to 2,500 when rounded to the nearest ten?
Savatey [412]
2504, as 2499 is 5 less, yet rounds to 2.5K. It is the highest possible for rounding to the tens, as 2505 rounds to 2510.
5 0
3 years ago
Read 2 more answers
The temperature in Scottsdale increased by 2 degrees in 2 days. If the temperature changed by the same
Vsevolod [243]

Answer:

yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh

Step-by-step explanation:yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era csacasccacwoh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh

5 0
2 years ago
How do you right 2.1 in words
Lelu [443]
Answer: Two and one tenth.
5 0
3 years ago
Find the variance of this probability distribution. Round to two decimal places.​
attashe74 [19]

Answer:

Variance = 4.68

Step-by-step explanation:

The formula for the variance is:

\sigma^{2} =\frac{\Sigma(X- \mu)^{2}}{N} \\or \\ \sigma^{2} =\frac{\Sigma(X)^{2}}{N} -\mu^{2} \\

Where:

X: Values \\\mu: Mean \\N: Number\ of\ values

The mean can be calculated as each value multiplied by its probability

\mu = 0*0.4 + 1*0.3 + 2*0.1+3*0.15+ 4*0.05=1.15

\frac{\Sigma (X)^{2}}{N} =\frac{(0^{2}+1^{2}+2^{2}+3^{2}+4^{2})}{5} =6

Replacing the mean and the summatory of X:

\sigma^{2} = \frac{\Sigma(X)^{2}}{N} -\mu^{2} \\= 6 - 1.15^{2}\\= 4.6775

4 0
4 years ago
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