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saul85 [17]
3 years ago
7

Use the table above to graph the function y = 2x - 2 with the domain (1,2,3).

Mathematics
1 answer:
rosijanka [135]3 years ago
8 0
Domain is the value for x. Substitute the domain values into the equation where the x is and get your answer. Ex: 2x-2 --> 2(1)-2=0 so plot a point (1,0) where x is 1 and y is 0. Do the same for other two points.
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IM PUTTING THIS FOR 30 POINTS PLEASE ANSWER
salantis [7]

Answer:

2(Jill) - 20 + (Jill) = 205

3(Jill) = 225

(Jill) = 75

(Jack) = 2(75) - 20 => 150 - 20 = 130

Jill= 75

Jack= 130

Step-by-step explanation:

6 0
3 years ago
Which substances dissolve in water? Check all of
Arturiano [62]

Answer:

polar liquids and polar solids

Step-by-step explanation:

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4 years ago
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use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 )​, (15 comma
lyudmila [28]

Answer:

volume V of the solid

\boxed{V=\displaystyle\frac{125\pi}{12}}

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.  

Each slice is a quarter of cylinder 5/n thick and has a radius of  

-k(5/n) + 5  for each k = 1,2,..., n (see picture)

So the volume of each slice is  

\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}

for k=1,2,..., n

We then add up the volumes of all these slices

\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}

Notice that the last term of the sum vanishes. After making up the expression a little, we get

\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2

But

\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)

we also know that

\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}

and

\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}

so we have, after replacing and simplifying, the sum of the slices equals

\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}

and the volume V of our solid is

\boxed{V=\displaystyle\frac{125\pi}{12}}

3 0
3 years ago
5. Evaluate the function for the given variables.
UkoKoshka [18]

Answer:

C. f(5) = 13 and f(-3) = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 3

x = 5

x = -3

<u>Step 2: Evaluate</u>

x = 5

  1. Substitute:                    f(5) = 2(5) + 3
  2. Multiply:                        f(5) = 10 + 3
  3. Add:                              f(5) = 13

x = -3

  1. Substitute:                    f(-3) = 2(-3) + 3
  2. Multiply:                        f(-3) = -6 + 3
  3. Add:                              f(-3) = -3
7 0
3 years ago
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In the function y-1 = (4x)² + 7, what effect does the number 4 have on
bija089 [108]

Answer:

D. It shrinks the graph horizontally to 1/4 the original width.

Step-by-step explanation:

f(px): |p|>1 horizontal compression   (x,y) -> (x/p , y)

8 0
3 years ago
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