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suter [353]
4 years ago
14

On a cold winter's day, if you left a cup of water sitting outside, it could freeze. Heat is transferred out of the water. Descr

ibe the behavior of the water molecules and how temperature is affected.
Chemistry
2 answers:
Verizon [17]4 years ago
4 0

Explanation:

When a cup of water is left outside it could freeze because thermal energy of water gets transferred to the atmosphere. As a result, the temperature of water will decrease due to cooling effect.

Therefore, molecules of water will lose kinetic energy and the molecules come closer to each other. So, force of attraction between the molecules will increase.

Hence, water will freeze.

agasfer [191]4 years ago
3 0
Well, when you leave the water outside, the molecules start to lose some thermal energy and they stop moving, making them more solid and less able to move around. Then, the water turns into ice.
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calculate the atomic mass of element X, if it has 2 naturally occurring isotopes with the following masses and natural abundance
jeka57 [31]
Hey there!

To find this, you should:

1) multiply the percentage (but in a decimal form) of each isotope by the mass.
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3) make sure to check for significant figures and you’re done!

Hope this helps :)
4 0
3 years ago
For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
Salsk061 [2.6K]

The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3                           N = +5                        

O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

     NO2– -----> NO3–

     Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

     NO2– + H2O -----> NO3–

     Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

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     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

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     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

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3 years ago
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3 years ago
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BartSMP [9]

Answer:

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Answer:

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