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sammy [17]
3 years ago
12

What is the grams of molar mass of magnesium

Chemistry
2 answers:
castortr0y [4]3 years ago
5 0
4.0359398 x 10^- 23 g
Luden [163]3 years ago
4 0

Answer:

4.0359398 × 10^-23 g

Explanation:

All explanations or thoughts led to that answer

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In an acid/base titration where NaOH(aq) is the titrant and HCl(aq) is the analyte, what is true about the moles of each reactan
ElenaW [278]

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<u>A</u><u>)</u><u> </u><u>The moles of NaOH are equal to moles of HCl.</u>

Explanation:

NaOH + HCl ↦NaCl + H20

7 0
3 years ago
T. Svedberg measured the molecular weight of carbonyl hemoglobin by velocity centrifugation. In this experiment, 0.96 g of prote
Natalija [7]

Answer:

The molecular weight is 77.7 kg/mol

Explanation:

The molecular mass of hemoglobin is equal to:

M=\frac{RTs}{D(1-Vp)}

Where

R = molar gas constant = 8.315 J/K mol

p = density = 0.998 g/mL

V = specific volume = 0.755 mL/g

s = sedimentation rate = ?

D = diffusion rate = 7x10⁻¹¹m²/s

T = temperature = 303 K

The sedimentation rate is equal to:

s=\frac{1}{w^{2}t } ln(\frac{x_{b,t} }{x_{b,0} } )

Where

w = angular velocity = 39300 rpm = 246929.18 rad/min

xb,30 = boundary midpoint distance at 30 min = 4.525 + 0.074 cm

t = time = 30 min

xb,0 = boundary midpoint distante at 0 min = 4.525 cm

s=\frac{1}{246929.18^{2}*30 } ln(\frac{4.525+0.074}{4.525} )=8.87x10^{-13} min=5.32x10^{-13} s

The molecular weight is:

M=\frac{8.315*303*5.32x10^{-13} }{7x10^{-11}*(1-(0.755*0.998)) } =77.7kg/mol

5 0
3 years ago
How much H2O is produced when 20000 g of C2H2 burns completely? Answer in units of g.
IgorC [24]

Answer:

Explanation:

H  = 1

C = 12

O = 16

Acetylene, HC≡CH = 2+24 = 26

H2O = 2 + 16 = 18

In XS oxygen, one HC≡CH yields one H2O

26 g HC≡CH  ==> 18 g H2O

2000 g HC≡CH ==> 2000*18/26 g H2O =  1384.6154 g H2O

3 0
3 years ago
⦁answer Calculate the density in g/L of 478 mL of krypton at 47° C and 671 mm Hg. ⦁ Determine the molar mass of a gas that has a
STALIN [3.7K]

Answer:

The correct answers are:

- Krypton: density= 2.8 g/L

- Molar Mass= 63.99 g/mol

- Mass of O₂= 15.29 g

Explanation:

The general equation of an ideal gas is the folllowing:

P x V = n x R x T

Where: P= pressure (in atm), V= volume; n= number of moles, R= gas constant (0,082 L.atm/K.mol) and T= temperature (in K).

<u>For krypton</u>:

P= 671 mmHg = 0,882 atm

V= 478 ml x 1000 ml/1 L= 0,478 L

T= 47ºC= 320 K

MM= 83.8 g/mol (from Periodic Table, Kr is an inert gas so it is a monoatomic gas)

P x V = n x R x T

Since the number of moles of a compound can be calculated by dividing the mass of compound (m) into its molar mass (MM):

n= m/MM

We can replace the expression in the first equation to obtain:

P x V= \frac{m}{MM} x R x T

m/V= \frac{P x MM}{R x T}

Density (d) is equal to the mass per volume (m/V), so we can directly calculate the density:

d= m/V= \frac{P x MM}{R x T}=

           = (0.882 atm x 83.8 g/mol)/(0.082 L.atm/K.mol x 320 K)

           = 2.81 g/L

<u>For the gas:</u>

d= 2.18 g/L

T= 66ºC= 339 K

P= 720 mmHg= 0.947 atm

d= \frac{P x MM}{R x T}

⇒MM = \frac{dx R x T}{P}

         = (2.18 g/L x 0.082 L.atm/K.mol x 339 K)/(0.947 atm)

         = 63.99 g/mol ≅ 64 g/mol

<u>For the O₂</u>:

V= 5.60 L

P= 1.75 atm

T= 250 K

MM(O₂) = 2 x Atomic Mass O= 2 x 16 g/mol= 32 g/mol

We can use the second equation:

P x V= \frac{m}{MM} x R x T

⇒  m = \frac{P x V x MM}{R x T}= (1.75 atm x 5.6 L x 32 g/mol)/(0.082 L.atm/K.mol x 250 K)

                         = 15.29 g≅ 16 g

4 0
3 years ago
Read 2 more answers
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irinina [24]

What's the question?

8 0
4 years ago
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