As Sun rises in the morning everyday and the heat energy radiations given by the Sun falls on a number of objects on our surroundings. As a result, the objects absorb this heat energy till afternoon due to which they become hot.

Hence, atoms of the objects gain kinetic energy due to which they move quickly. This shows that the temperature of the object (sand here) increases.

When Maria walked in the same area in the afternoon, the sand was hot as its particles have gained kinetic energy due to which they move rapidly from one place to another. Hence, sand feels more hot in the afternoon in the same area where she walked.

Thus, we can conclude that the statement the atoms in the sand were moving more quickly best describes why the temperature of the sand increased.

3 0

2 years ago

One of the products when aqueous Na, CO, reacts with aqueous

mixas84 [53]

Answer:

NaNO3

balanced equation - Na2CO3 + Sn(NO3)2 → 2NaNO3 + Sn(CO3)

6 0

2 years ago

Which one is it? Please help

DedPeter [7]

Answer:

D: 60 grams.

Explanation:

If you look at the x-axis and where it says 50 degrees Celsius, you can see that it takes 20 grams of solute to be saturated at 100 GRAMS of solvent. However, the question is asking for the amount of solute to saturate a 300 GRAM solution.

This means you will have to multiply the amount of solute needed at 100 grams by 3 to get you to the amount needed for 300 grams.

20 times 3 will get you to your answer, 60 grams.

6 0

3 years ago

Identify the correct coefificients to balance it<br> -C3H8+O2 to -CO2 +-H2O

Iteru [2.4K]

Answer:

${\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

Explanation:

${\rm ?\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}$ .

Among the four species in this reaction, $\rm C_3H_8$ is species with the largest number of atoms per molecule. Assume that the coefficient of this compound is $1$ .

${\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}$ .

Number of atoms on the left-hand side of the reaction:

$\rm C$ : $1 \times 3 = 3$ .
$\rm H$ : $1 \times 8 = 8$ .
$\rm O$ : not found yet.

By the conservation of atoms, the number of atoms on the right-hand side of the reaction should match those on the left-hand side. In this reaction, $\rm CO_2$ is the only product with carbon atoms, whereas $\rm H_2O$ is the only product with hydrogen atoms. These $3$ carbon atoms and $8$ hydrogen atoms would correspond to:

$3 / 1 = 3$ $\rm CO_2$ molecules, and
$8 / 2 = 4$ $\rm H_2O$ molecules.

${\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

Number of atoms on the right-hand side of the reaction:

$\rm C$ : $3 \times 1 = 3$ .
$\rm H$ : $4 \times 2 = 8$ .
$\rm O$ : $3 \times 2 + 4 \times 1 = 10$ .

The number of $\rm O$ atoms on the left-hand side should match those on the right-hand side. In this reaction, $\rm O_2$ is the only reactant with $\rm O\!$ atoms. These $10$ $\rm \! O$ atoms would correspond to:

$5$ $\rm O_2$ molecules.

${\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}$ .

5 0

2 years ago