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Alex Ar [27]
3 years ago
12

As pressure decreases, density:

Chemistry
2 answers:
Effectus [21]3 years ago
6 0
As pressure decreases, density A. decreases.

Or the volume has grown larger, but A should be your answer
Zanzabum3 years ago
4 0

Answer:

A. decrease

Explanation:

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C(s)+H2(g)-> C2H6(g)
disa [49]

Explanation:

2 C(s) + 3 H2(g) = C2H6(g)

5 0
3 years ago
Why is air humid and weather wet at low pressure belts
natima [27]
In low-pressure belts, there is an absence of surface winds because winds approaching them rise near their margin. This causes vertical currents. when they pass along the ocean, they suck up a lot of water and get a lot of moisture, thus giving wet and humid weather.
3 0
4 years ago
If all of the energy from burning 281.0 g of propane (ΔHcomb,C3H8 = –2220 kJ/mol) is used to heat water, how many liters of wate
lapo4ka [179]

This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.

<h3>Combustion:</h3>

In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Hence, we can calculate the heat released from this reaction by using the mass, which has to be converted to moles, and the given enthalpy of combustion:

Q=281.0g*\frac{1mol}{44.09g}*-2220\frac{kJ}{mol}*\frac{1000J}{1kJ}\\ \\ Q=-1.415x10^7 J

<h3>Calorimetry:</h3>

In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

Q=mC\Delta T

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

m=\frac{Q}{C\Delta T} =\frac{1.415x10^7J}{4.184\frac{J}{g\°C}(100.0\°C-20.0\°C)}\\ \\m=4.227x10^4g

Finally, we convert it to liters as required:

V=4.227 x10^4g*\frac{1mL}{1.00g}*\frac{1L}{1000mL}  \\\\V=42.27L

Learn more about calorimetry: brainly.com/question/1407669

4 0
2 years ago
How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm
Citrus2011 [14]

<u>We are given:</u><u>_______________________________________________</u>

Volume of Gas (V) = 2.5L

Pressure (P) = 1.2 atm

Temperature (T) = 25°C  OR 25+273 = 298 K

Universal Gravitational Constant (R) = 0.0821

<u>Solving for number of moles:</u><u>___________________________________</u>

From the Ideal Gas Equation,

PV = nRT

(1.2)(2.5) = n(0.0821)(298)           [plugging the given values]

n = [(1.2)(2.5)] / [0.0821*298]

n = 300 / [298*8.21]

n = 0.12 moles

Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C

7 0
3 years ago
Which factor affects a solute's solubility rather than its rate of solution?
Illusion [34]

Answer: A

Explanation:

I took the test it was A

4 0
3 years ago
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