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alexandr402 [8]
3 years ago
15

Which factor affects a solute's solubility rather than its rate of solution?

Chemistry
1 answer:
Illusion [34]3 years ago
4 0

Answer: A

Explanation:

I took the test it was A

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The solid XY decomposes into gaseous X and Y: XY(s) m X(g) + Y(g) Kp = 4.1 (at 0 °C) If the reaction is carried out in a 22.4 L
tia_tia [17]

Answer:

None of the conditions will favor either the forward reaction or backward reaction , hence the answer is D

Explanation:

  • The principle of chemical Equilibrium is applied here, where the concentration of the reactants or the forward reaction is same as the concentration of the products or the backward reaction.

  • The equilibrium constants is also involved here, K can be in terms of pressure (Kp) or concentration (Kc) hence equilibrium constant is the ration of the concentration of the products to the concentration of the reactants raised to the power of the coefficient of the reactants and products.
  • Partial pressure , total pressure and the mole fraction relationship is also applied
  • The step by step explanation is as shown in the attachment below.

4 0
3 years ago
What is the pH of a solution with a concentration of 2.4 × 10-5 molar H3O+? Show, or explain, the work used to solve this proble
MrRissso [65]
pH=-log|H_{3}O^{+}|\\\\
pH=-log2.4*10^{-5}=-(log2.4+log10^{-5})=-(0,38-5)=-(-4.62)\\\\
pH=4.62
7 0
3 years ago
Read 2 more answers
Two elements that have properties similar to those of the element potassium(K). To those of krypton(Kr)
balu736 [363]

Answer:

Calcium (Ca) and Scandinavium (Sc)

Explanation:

They are all on the same period.

8 0
3 years ago
Someone please help me, i really need help!
barxatty [35]

Answer:

2 Moles

Explanation:

12 grams of carbon contains 1 mole

1 gram contains [1 mole/ 12 grams ] x 1 gram

24 grams contains [1 mole/ 12 grams ]* 24 gram = 2 moles.

5 0
3 years ago
For the following electrochemical cell, determine the oxidizing agent, reducing agent, and whether the cell is a voltaic cell or
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1637947 d hdidmbdjrn
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