Predict the initial and isolated products for the reaction. The starting material is a 6 carbon chain where there is a triple bo
nd between carbons 3 and 4. This reacts with H 2 O, H 2 S O 4, and catalytic H g 2 plus to form an initial product. The initial product converts to the more stable isolated product but is in equilibrium. Hint: the products are isomers and in equilibrium with each other.
1 answer:
Answer:
See explanation and image attached
Explanation:
This reaction is known as mercuric ion catalyzed hydration of alkynes.
The first step in the reaction is attack of the mercuric ion on the carbon-carbon triple bond, a bridged intermediate is formed. This bridged intermediate is attacked by water molecule to give an organomercury enol. This undergoes keto-enol tautomerism, proton transfer to the keto group yields an oxonium ion, loss of the mercuric ion now gives equilibrium keto and enol forms of the compound. The keto form is favoured over the enol form.
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Answer : The equilibrium constant for this reaction is,
Explanation :
The given main chemical reaction is:
;
The intermediate reactions are:
(1) ;
(2) ;
We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:
(1) ;
(2) ;
Thus, the equilibrium constant for this reaction will be:
Thus, the equilibrium constant for this reaction is,
Answer:
4.5g/mL
Explanation:
Given parameters:
Mass of ball = 36g
Volume of the ball = 8mL
Unknown:
Density of the ball = ?
Solution:
Density is the mass per unit volume of a substance.
Density =
So;
Density = = 4.5g/mL