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Tanya [424]
3 years ago
10

Predict the initial and isolated products for the reaction. The starting material is a 6 carbon chain where there is a triple bo

nd between carbons 3 and 4. This reacts with H 2 O, H 2 S O 4, and catalytic H g 2 plus to form an initial product. The initial product converts to the more stable isolated product but is in equilibrium. Hint: the products are isomers and in equilibrium with each other.

Chemistry
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

See explanation and image attached

Explanation:

This reaction is known as mercuric ion catalyzed hydration of alkynes.

The first step in the reaction is attack of the mercuric ion on the carbon-carbon triple bond, a bridged intermediate is formed. This bridged intermediate is attacked by water molecule to give an organomercury enol. This undergoes keto-enol tautomerism, proton transfer to the keto group yields an oxonium ion, loss of the mercuric ion now gives equilibrium keto and enol forms of the compound. The keto form is favoured over the enol form.

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An airplane travels with a constant velocity of 210 m/s and in the upper atmosphere where the plane is traveling there is a wind
kolezko [41]

Answer:

hello your question is incomplete the options are missing

Determine the resultant velocity for the plane when it is travelling

i) To the east

ii) To the west

answer :i)  270 i

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Explanation:

velocity of Airplane = 210 m/s

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The resultant velocity for the plane when it is travelling  

let the velocity of the wind = V2

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Vr = V2 i  + V1 i

Vr= 60i + 210i  = 270i

ii) resultant velocity when the plane is travelling to the west

Vr = - V1 i + V2i

     = -210i  + 60 i = -150 i  

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