Add the like terms. So I'll add the variables. 8x+6x is 14x. Now add whole numbers. 30+10 is 40. Our new expression we'll be 14x+40=180. Subtract 40 from 180. 180-40=140. Now we have the expression 14x=140. 140 divided by 14 is 10. So x is 10.

7 0

3 years ago

[25 POINTS] The approximate change in the value of f(x) = sqrt(2(x-1)) at x = 3 using differentials with dx = 0.01 is

otez555 [7]

Answer:

$\frac{1}{200}$

Step-by-step explanation:

<u>Find the derivative of the function when x=3</u>

<u /> $y=\sqrt{2(x-1)}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(x-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(3-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(2)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{4}}$

$\frac{dy}{dx}=\frac{1}{2}$

Since the change in the value of the function is $dy$ and we know that the change in x is $dx=0.01$ , then we have:

$\frac{dy}{dx}=\frac{1}{2}$

$dy=\frac{1}{2}dx$

$dy=\frac{1}{2}(0.01)$

$dy=\frac{1}{200}$

Therefore, the 2nd option is correct

<u />

8 0

2 years ago

What is “1 more than the product of a number (n) and -8” as an algebraic expression?

3241004551 [841]

Answer:

-8n+1

Step-by-step explanation:

the word product indicates multiplication and it says that the product is between n and -8 so we are multiplying -8 and n. 1 more indicates addition so we are adding 1 to the product of -8n.

5 0

3 years ago