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notsponge [240]
3 years ago
6

A pair of equations is shown below:

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
So, both equations are essentially linear equations.
Linear equations are written in the format y = mx+b, where m represents the slope/slope intercept and b represents the y-intercept.
---------------------------------------------------------------------------------------------------------------
Part A
the slope and y-intercept

y = mx +b
m - the slope; b- y-intercept

therefore;

y = 6x - 4
m = 6; b = -4

y = 5x - 3
m = 5; b = -3

The coordinates of the point where the lines are crossed are the solution to the system of linear equations.

How to graph the lines:
y = 6x - 4
y-intercept (0; -4)
for x = 1 ⇒ y = 6 · 1 - 4 = 6 - 4 = 2 ⇒ (1; 2)

y = 5x - 3
y-intercept (0; -3)
for x=1 ⇒ y = 5 · 1 - 3 = 5 - 3 = 2 ⇒ (1; 2)

***look at the img for graph reference***

Part B: x = 1; y = 2

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2x(5+3x)-x find the coefficient of x
s344n2d4d5 [400]

To start, we need to distribute

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