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notsponge [240]
3 years ago
6

A pair of equations is shown below:

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
So, both equations are essentially linear equations.
Linear equations are written in the format y = mx+b, where m represents the slope/slope intercept and b represents the y-intercept.
---------------------------------------------------------------------------------------------------------------
Part A
the slope and y-intercept

y = mx +b
m - the slope; b- y-intercept

therefore;

y = 6x - 4
m = 6; b = -4

y = 5x - 3
m = 5; b = -3

The coordinates of the point where the lines are crossed are the solution to the system of linear equations.

How to graph the lines:
y = 6x - 4
y-intercept (0; -4)
for x = 1 ⇒ y = 6 · 1 - 4 = 6 - 4 = 2 ⇒ (1; 2)

y = 5x - 3
y-intercept (0; -3)
for x=1 ⇒ y = 5 · 1 - 3 = 5 - 3 = 2 ⇒ (1; 2)

***look at the img for graph reference***

Part B: x = 1; y = 2

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Find the value of c so that (x-5) is a factor of the polynomial p(x)
liubo4ka [24]

I think the question is

Find the value of c so that (x-5) is a factor of the polynomial

p(x) = x^3 + 2x^2 + cx + 10

The other factor is going to be some quadratic.  We can say a few things about its coefficients but let's start by saying in general it's

q(x)= ax^2 + bx + k

p(x) = (x-5)q(x)

x^3 + 2x^2 + cx + 10 = (x-5)(ax^2 + bx+k) = ax^3 + (b-5a)x^2 + (k-5b)x - 5k

Equating respective coefficients,

a=1

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so we get

b = 2 + 5 = 7

k = 10/-5 = -2

c = k - 5b = 2 - 5(7)= -37

Answer: -37

Check:

(x^2 + 7x - 2)(x - 5) = x^3 + 2 x^2 - 37 x + 10\quad\checkmark




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