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ale4655 [162]
3 years ago
15

\frac{2z( x^{2} - y}{xy + z} " alt=" \frac{2z( x^{2} - y}{xy + z} " align="absmiddle" class="latex-formula"> these are the numbers for the variables x=-1 y=6 z=4
Mathematics
1 answer:
FrozenT [24]3 years ago
7 0
I use those variables in the second xy+z and i got this 

<span><span>−<span><span>12<span>x^2</span></span>z</span></span>+<span><span>12y</span>z</span></span>+<span>4</span>
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Answer:

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Step-by-step explanation:

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Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
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Using the fundamental counting theorem, we have that:

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The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

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8 \times 9 \times 9 = 648

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For the number of 10-digit phone numbers:

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Then

648 \times 10^7 = 6,480,000,000&#10;

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0
2 years ago
How many solutions does y=1/2x have
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P(t)=number of sheet of paper after t minutes.
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Answer: the printer prints 100 sheets of paper in 12.5 minutes.
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3 years ago
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