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sashaice [31]
3 years ago
11

Write the expression in standard form. six divided by quantity four minus thirteen i.

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
7 0

Answer:

\frac{6}{4} - 13i

Step-by-step explanation:

six divided by quantity four minus thirteen i

Standard form of the expression is a+bi

six divided by quantity four means we divide 6 and 4

six divided by quantity four is \frac{6}{4}

Now minus thirteen i

So we subtract 13i from the fraction

\frac{6}{4} - 13i

It is in the form of a+bi

dangina [55]3 years ago
4 0
6\frac{6}{4-13i}

I'm not sure if the i is supposed to be there or not. Is it a variable that is connected to 13?
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my question is 2x^2+13x+6=0 HOW???? there are no numbers that multiply to 6 and can add to 13. Please help I'm so confused!!!
kondor19780726 [428]
Look

2x^2+13x+6
factored into
(ax+b)(cx+d)
we need to find a,b,c,d such that when multipied we get 2x^2+13x+6
first
we know that the first number hast to be 2
(2x+somethin)(1x+sometin)
and the end numbers have to multiply to 6
if we try 1 and 6
(2x+1)(x+6)=
2x^2+x+12x+6=
2x^2+13x+6
correct

so
2x^2+13x+6=0=(2x+1)(x+6)

therefor assume
2x+1=0 and x+6=0

2x+1=0
minus 1
2x=-1
divide 2
x=-1/2

other one
x+6=0
mnus 6
x=-6

x=-6 or -1/2


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