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3 years ago

Which of the following natural features is formed by weathering, erosion, and deposition?

Physics

2 answers:

Otrada [13]3 years ago

7 0

The answer is d. sand dunes

Black_prince [1.1K]3 years ago

7 0

Answer:

Sand dunes

Explanation:

Dunes are hills of sand which are formed by the action of winds which is an agent of weathering. Sand dunes usually formed along the beach or in a desert. Sand dunes form when the wind blows, they carry particles of sand before they drop to the ground. As they roll and bounce on the ground, sand particles create small, wave-shaped ripples of sand. These ripples can build up into larger structures.

Dunes can grow very high say up to 4000 feet and be many miles long. Dunes can be various shapes such as crescents, stars, or just repeated lines.

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A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per m

Natali [406]

(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

<h3>Electric field at a point on the Gaussian surface</h3>

The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;

E = λ/2πε₀r

where;

λ is linear charge density
ε₀ is permitivity of free space
r is the position of the charge

<h3>At a distance of 5.5 m</h3>

$E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C$

<h3>At a distance of 2.5 m</h3>

$E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C$

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

Learn more about electric field here: brainly.com/question/14372859

4 0

2 years ago

Think about lifestyle choices that you make on a daily basis. Choose at least four lifestyle choices which you could change to i

miss Akunina [59]

Answer:

A.The four lifestyle choices which I could change are:

1. The amount of physical exercise I engage in on a daily basis.

2, The number of hours I sleep.

3. The quantity of junk foods I consume daily and

4. Cultivation of the habit of spending time alone daily.

B. My days are always very busy, so I do not engage at all in physical exercise. Adding at least a thirty minute of physical exercise to my daily tasks will improve my health considerable. Due to the nature of my day, I usually eat on the move, thus I eat junk foods everyday. Eating healthy and balanced diet will go a long way in improving my health. I sleep for three hours only everyday, from 2 am to 5 am. This is because I have to leave my house very early in the morning and I don't usually get to sleep until 2 am in the morning. Spending more hours sleeping will improve my overall health. I want to start spending at least 30 minutes alone on a daily basis in order to meditate and to reflect over the events of the day. This will be a great boost to my mental health.

There you go boo, hope this helps!!!!

3 0

3 years ago

Read 2 more answers

Environment includes _______.

insens350 [35]

D should be correct.

6 0

4 years ago

Which statement correctly describes sound waves

Alexxandr [17]

Answer:

Sound waves are longitudinal waves

Explanation:

Sound waves are the longitudinal waves. In longitudinal waves, the particles of the wave move parallel to the direction of propagation of waves.

It moves in the form of compression and rarefaction. When the particles are compact in a space the compression occurs while when they far apart form each other rarefaction occurs.

3 0

3 years ago

If the depth of water in a well is 10m, what is the pressure exerted by it the bottom of the well ? ( Use g = 10 m/s2)

Tasya [4]

Answer:

The precise answer depends on the density and therefore the temperature of the water, but we can obtain a reasonable approximation by assuming that the density of the water is 1000 kilograms per cubic meter (kg/m³).

Since the depth of the water in the well is 10 m, the volume of water directly above an area A of a square meters (m²) at the bottom of the well is 10×a m³.

Since the density of the water is 1,000 kg/m³, the mass of water directly above area A is (1,000 kg/m³) × (10×a m³) = (1000×10×a kg) = 10,000×a kg.

Since g = 9.8 m/s², the force of gravity acting on the water directly above area A is (9.8 m/s²) × (10,000×a kg) = 9.8×10,000×a N (newtons) = 98,000×a N.

So the pressure of water acting on area A is (98,000×a N)/(a m²) = (98,000×a)/a N/m² = 98,000 pascals (pa). And since A could be any given area at the bottom of the well, this is the pressure at any point at the bottom of the well.

So the pressure at the bottom of the well is 98,000 pascals (or 98,000/101,325 standard atmospheres = 560/579 atmospheres ~ 0.967 standard atmospheres).

Please comment below if you have any questions.

7 0

3 years ago