Conservation of momentum: total momentum before = total momentum after
Momentum = mass x velocity
So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32
Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32
Therefore β = 12.8 m/s
The volume of the water, which was initially 100mL changed to 96mL after refrigeration because the volume of water reduces when cool.
<h3>Why does water change in volume?</h3>
Water is a substance that is known for its unique characteristics that makes it stand out among all other liquids.
One notable feature of water is it's ability to become denser when subjected to cooler temperatures i.e. water is more dense when cold.
As water cools or becomes less warm, it contracts and decreases in volume. When water decreases in volume, it becomes more dense.
Therefore, according to this question, it can be said that the volume of the water, which was initially 100mL changed to 96mL after refrigeration because the volume of water reduces when cool.
Learn more about water volume at:brainly.com/question/17322215
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Answer:
<u>2.48 m</u> is the length of the rope.
Explanation:
Cycle period is 321
Time is 20 second
Wave travels at speeds = 26.4 m/s
We know that,

Frequency required for 321 complete cycle in 20 seconds is

Frequency = 16.05 hz
We know that,


λ = wavelength, the distance between "wave crests" (m)
v = wave velocity, the "speed" that waves are moving in a direction (m/s)
f = frequency, (cycles/ or Hz)

λ = 1.65 m
As per given question "length of the rope has three equal length segment"



Length of the rope = 2.48 m
Therefore, length of the rope is <u>2.48 m.</u>
Answer:
E= 2.158× 10*5N/C
Explanation:
K= 8.99×10*9, q= 6×10*-6C, d= 0.5m
E= kq/d*2
E= (8.99×10*9× 6×10*-6)/0.5*2
E= 215760
E= 2.158 ×10*5N/C
Answer:
4.096 kW
Explanation:
Applying,
P = Fvcos∅................. Equation 1
Where P = Power of the motor, F = Force exerted on the motor, v = Velocity, ∅ = angle.
From the question,
Given: F = 500 N, v = 10 m/s, ∅ = 35°
Substitute these values into equation 1
P = 500×10×cos35°
P = 4095.8 W
P = 4.096 kW
Hence the power rating of the moto in kW is 4.096 kW