Answer:
0.074 V
Explanation:
Parameters given:
Number of turns, N = 121
Radius of coil, r = 2.85 cm = 0.0285 m
Time interval, dt = 0.179 s
Initial magnetic field strength, Bin = 55.1 mT = 0.0551 T
Final magnetic field strength, Bfin = 97.9 mT = 0.0979 T
Change in magnetic field strength,
dB = Bfin - Bin
= 0.0979 - 0.0551
dB = 0.0428 T
The magnitude of the average induced EMF in the coil is given as:
|Eavg| = |-N * A * dB/dt|
Where A is the area of the coil = pi * r² = 3.142 * 0.0285² = 0.00255 m²
Therefore:
|Eavg| = |-121 * 0.00255 * (0.0428/0.179)|
|Eavg| = |-0.074| V
|Eavg| = 0.074 V
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
The tension is 
b
The time taken is 
c
The position for maximum velocity is
S = 0
d
The maximum velocity is
Explanation:
The free body for this question is shown on the second uploaded image
From the question we are told that
The mass of the bob is 
The angle is 
The length of the string is 
The tension on the string is mathematically represented as

substituting values


The motion of the bob is mathematically represented as

=> 
Where
is the angular speed
and
is the phase change
At initial position S = 0
So 

Generally
can be mathematically represented as

Where T is the period of oscillation which i mathematically represented as

So



substituting values


Looking at the equation

We see that maximum velocity of the bob will be at S = 0
i. e 
The maximum velocity is mathematically represented as

Where A is the amplitude which is mathematically represented as

So

Recall 
substituting values
Answer:
Wavelength = <u>1.5 m</u>
Explanation:
The formula for waves in terms of wavelength, speed and frequency is:
Speed (v) = Frequency (f) × Wavelength (λ)
33 = 22 × λ
33 = 22λ
λ = 
So, λ = 1.5 m
Answer: the electromagnetic spectrum
Explanation:
I’m not sure but I think this is it!
Answer:
A) d_o = 20.7 cm
B) h_i = 1.014 m
Explanation:
A) To solve this, we will use the lens equation formula;
1/f = 1/d_o + 1/d_i
Where;
f is focal Length = 20 cm = 0.2
d_o is object distance
d_i is image distance = 6m
1/0.2 = 1/d_o + 1/6
1/d_o = 1/0.2 - 1/6
1/d_o = 4.8333
d_o = 1/4.8333
d_o = 0.207 m
d_o = 20.7 cm
B) to solve this, we will use the magnification equation;
M = h_i/h_o = d_i/d_o
Where;
h_o = 3.5 cm = 0.035 m
d_i = 6 m
d_o = 20.7 cm = 0.207 m
Thus;
h_i = (6/0.207) × 0.035
h_i = 1.014 m