Answer:
Q = A ⊕ B = (A AND B) + ( not(A) AND not(B) )
Explanation:
AND gates : only output 1 when both inputs are 1
OR gate: only output 1 when either or both of the inputs are 1
NOT gates: takes only one input ad output the opposite of the input
The required circuit should takes two inputs and outputs a 1 if and only if the two inputs are the same signal.
The two possible scenarios : both input are 1's or 0's
Q = A ⊕ B = (A AND B) + ( not(A) AND not(B) )
A B not(A) not(B) A AND B not(A) AND not(B) Q
0 0 1 1 0 1 1
0 1 1 0 0 0 0
1 0 0 1 0 0 0
1 1 0 0 1 0 1
Answer:
time is 0.42 sec
Explanation:
Given data
radius = 23 m
angular acceleration = 5.7 rad/s²
to find out
time
solution
we know that radius is constant so that
tangential acceleration At = angular acceleration × radius ............. 1
tangential acceleration = 5.7 × 23 = 131.1 m/s²
and
radial acceleration Ar = (angular velocity)² × radius ........................2
we consider angular velocity = ω
this is acting toward center
so
compare 1 and 2
At = Ar
5.7 r =ω³ r
ω = √5.7 = 2.38746 rad/s
so
ω = 5.7 t
2.387 = 5.7 t
t = 2.387 / 5.7
t = 0.4187
time is 0.42 sec
Answer:
The energy of one photon is 2.21x10⁻²⁴ J. Multiplied by 10²⁵ is 22.10 J.
Explanation:
The energy (E) of a photon is:
Where:
h: is the Planck's constant = 6.62x10⁻³⁴ J.s
λ: is the wavelength of the radiation = 8.97 cm
c: is the speed of light = 3.00x10⁸ m/s
Hence, the energy of one photon is 2.21x10⁻²⁴ J.
Now, if we multiply the answer by 10²⁵ we have:
I hope it helps you!
Answer:
Bank angle = 35.34o
Explanation:
Since the road is frictionless,
Tan (bank angle) = V^2/r*g
Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2
Tan ( bank angle) = 40^2/(230*9.81)
Tan (bank angle) = 0.7091
Bank angle = tan inverse (0.7091)
Bank angle = 35.34o
I think it would be plum pudding, solid ball, solar system.
