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Makovka662 [10]
2 years ago
5

If you given volume. for example 200 cm³ how can you change it to area m²​

Physics
1 answer:
PIT_PIT [208]2 years ago
7 0

Answer:

move the decimal 6 places to the left.

Explanation:

um I assume you meant to say area m^3

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We wrap a light, nonstretching cable around a 8.00 kg solid cylinder with diameter of 30.0 cm. The cylinder rotates with negligi
antoniya [11.8K]

Answer:

h = 16.67m

Explanation:

If the kinetic energy of the cylinder is 510J:

Kc=510=1/2*Ic*\omega c^2

\omega c=\sqrt{510*2/Ic}

Where the inertia is given by:

Ic=1/2*m_c*R_c^2=1/2*(8)*(0.15)^2=0.0225kg.m^2

Replacing this value:

\omega c=106.46rad/s

Speed of the block will therefore be:

V_b=\omega_c*R_c=106.46*0.15=15.969m/s

By conservation of energy:

Eo = Ef

Eo = 0

Ef = 510+1/2*m_b*V_b^2-m_b*g*h

So,

0 = 510+1/2*m_b*V_b^2-m_b*g*h

Solving for h we get:

h=16.67m

3 0
3 years ago
Can someone help me with this activity?
Inessa05 [86]
What class is that in if math or biology I’m not good that
8 0
3 years ago
A car is driving 55 miles per hour east. The car changes direction to head north but still travels at 55 miles per hour. Which i
bezimeni [28]

Answer:

Just as distance and displacement have distinctly different meanings (despite their similarities), so do speed and velocity. Speed is a scalar quantity that refers to "how fast an object is moving." Speed can be thought of as the rate at which an object covers distance. A fast-moving object has a high speed and covers a relatively large distance in a short amount of time. Contrast this to a slow-moving object that has a low speed; it covers a relatively small amount of distance in the same amount of time. An object with no movement at all has a zero speed.

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2 years ago
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satela [25.4K]

a) mass

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8 0
3 years ago
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A large spool in an electrician's workshop has 55 m of insulation coated wire coiled around it. when the electrician connects a
goblinko [34]

Answer:

21.2 m

Explanation:

The current in the wire is given by Ohm's law:

I=\frac{V}{R}

where V is the voltage of the battery and R is the resistance of the wire.

The resistance of the wire is directly proportional to the length of the wire, so we can write:

R=kL

where k is a constant and L is the length of the wire. Substituting into the first equation,

I=\frac{V}{kL}

We can rewrite this equation also as

\frac{V}{k}=IL

where the term on the left is a constant (because the voltage of the battery does not change). So, we can write:

I_1 L_1 = I_2 L_2

where:

I_1 = 1.0 A is the current in the first situation

L_1 = 55 m is the length of the wire in the first situation

I_2 = 2.6 A is the current in the second situation

L_2=? is the length of the wire in the second situation

Re-arranging the formula, we can find the value of L2:

L_2 = \frac{I_1 L_1}{I_2}=\frac{(1.0 A)(55 m)}{2.6 m}=21.2m

8 0
3 years ago
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