Answer:
7.9060 m²
8.57 Volts
5.142×10⁻⁶ Joule
1.2×10⁻⁶ Coulomb
Explanation:
C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F
d = Distance between plates = 0.5 mm = 0.5×10⁻³ m
Q = Charge = 1.2 μC = 1.2×10⁻⁶ C
ε₀ = Permittivity = 8.854×10⁻¹² F/m
Capacitance
∴ Area of each plate is 7.9060 m²
Voltage
∴ Potential difference between the plates if the capacitor is charged to 1.2 μC is 8.57 Volts.
Energy stored
E=0.5CV²
⇒E = 0.5×0.14×10⁻⁶×8.57²
⇒E = 5.142×10⁻⁶ Joule
∴ Stored energy is 5.142×10⁻⁶ Joule
Charge
Q = CV
⇒Q = 0.14×10⁻⁶×8.57
⇒Q = 1.2×10⁻⁶ C
∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb
Not really sure but...
<span>A metaphysical poet is a writer whose </span>focus is on universal human experiences.
hope this helps!...
<span>An ecosystem can only sustain so many organisms. That limit would be its carrying capacity. If the population goes above that number then other factors will cause the population to crash and then rebound to a constant level. </span>
Max height occurs when v = 0.
v(t) = ds(t)/dt
v(t) = 80 - 32t
0 = 80 - 32t
t = 5/2
s(5/2) = 80(5/2) - 16(5/2)^2
s(5/2) = 100
Answer: 100 ft
96 = 80t - 16t²
t = 3, 2
(80 ± √256) / 32 using the quadratic equation.
v(2) = 16
v(3) = -16
Simply be used as a reference point <span>to describe its position. a fact forming the basis of an evaluation or assessment; criterion. They had few cultural </span>reference points<span> in common.</span>
