Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))

8 0

3 years ago

Use an inequality to describe the interval of real numbers <br><br>(-3,8]

Naya [18.7K]

38 i think it means infinite

8 0

3 years ago

Use the method of completing the square to solve x2 - 6x + 1 = 0. Simplify your solutions.

exis [7]

Answer:

x = 3 ± 2 $\sqrt{2}$

Step-by-step explanation:

given

x² - 6x + 1 = 0 ( subtract 1 from both sides )

x² - 6x = - 1

To complete the square

add (half the coefficient of the x- term)² to both sides

x² - 6x + (- 3)² = - 1 + (- 3)²

x² - 6x + 9 = - 1 + 9

(x - 3)² = 8 ( take the square root of both sides )

x - 3 = ± $\sqrt{8}$ = ± 2 $\sqrt{2}$ ( add 3 to both sides )

x = 3 ± 2 $\sqrt{2}$

8 0

3 years ago

PLEASE HELP I’LL GIVE BRAINLIST.

kolezko [41]

Answer:

2/6 is probably your answer

Step-by-step explanation:

5 0

3 years ago