Answer:
1.Graphing the linear equations by constructing the table of values.
2.Graphing the linear equation using the slope and y-intercept (i.e. y=mx+b)
3.Graphing the linear equation by connecting x-intercept and y-intercept.
Step-by-step explanation:

Answer:
False, quadrant two has both negative and positive values.
Hope I helped. Good luck on the assignment!
Step-by-step explanation:
Answer:
-4
+3
12
-0.5, 12.25
x = -0.5
Step-by-step explanation:
The x intercepts are the values of x when y = 0 ie the roots of the equation

or

We can re-write the above as:
(x+4) (x-3) = 0
This gives the two roots as x = -4 and x = +3. Leftmost (smallest) root is -4 and rightmost(largest) root is +3
y intercept is when x = 0. Plugging into the original equation, y value at x = 0 is 12
Vertex x value is given by the formula -b/2a where a is the coefficient of x^2 and b the coefficient of x
Here a = -1, b= -1 so vertex x value = - (-1)/(-1).2 = - 1/2 = -0.5
Plugging this value of x into the original function gives the vertex y value

The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5
The graph of the quadratic function shows these values
Parallel lines have the same slope. So the slope of the other line =2/7
Answer:
25b3a+93b+60a=30a2+b2
Step-by-step explanation: