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const2013 [10]
4 years ago
14

If 2-fluoropentane could undergo an e1 reaction, would you expect the major product to be the more stable alkene or the less sta

ble alkene? explain your answer.
Chemistry
1 answer:
expeople1 [14]4 years ago
3 0
There are two products of 2-fluoropentane E₁ reaction: 1-pentene (minor product) and 2-pentene (major product). 2-pentene is major product and more stable because he is most substituted product  (Zaitsev's rule).
Zaitsev's rule<span> is an empirical rule for predicting the favored </span>alkene<span> product in </span>elimination reactions<span>.</span>

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A certain reaction has an enthalpy of Δ=44 kJ and an activation energy of a=61 kJ. What is the activation energy of the reverse
avanturin [10]

Answer:

E = 17 kJ

Explanation:

The enthalpy of the reaction is:

\Delta H = E_{p} - E_{r}  

<u>Where</u>:

Ep: is the energy of the products

Er: is the energy of the reactants

Similarly, the enthalpy of the reaction is related to the activation energy forward (E_{F}) and to the activation energy reverse (E_{R}) as follows:

\Delta H = E_{F} - E_{R}  

Having that ΔH = 44 kJ and E_{F} = 61 kJ, the activation energy of the reverse reaction is:

E_{R} = E_{F} - \Delta H = 61 kJ - 44 kJ = 17 kJ  

Therefore, the activation energy of the reverse reaction is 17 kJ.

I hope it helps you!

3 0
3 years ago
How do people start alcohol consumption​
Debora [2.8K]

Answer:

Explanation:Due to the mental pressure,

                       Due to peer pressure,

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6 0
3 years ago
I’ll give 5 stars and Brainliest plus this is 20 points lol
Daniel [21]

Answer:

I think is b

Explanation:

4 0
3 years ago
What is the OH in a solution made by adding 0.060 mole of calcium oxide to 500.0ml
Alex73 [517]

Answer:

0.24 mol/L.

Explanation:

  • Ca(OH)₂ dissociates in solution according to the equation:

<em>Ca(OH)₂ → Ca²⁺ + 2OH⁻.</em>

<em></em>

Every 1.0 mol of Ca(OH)₂ dissociates to give 2.0 moles of OH⁻.

∴ The no. of moles of OH⁻ produced from 0.06 mol of Ca(OH)₂ = (2 x 0.06 mol) = 0.12 mol.

<em>∴ [OH⁻] = no. of moles / V of the solution</em> = (0.12 mol)/(0.5 L) = <em>0.24 mol/L.</em>

8 0
4 years ago
1. What is the molarity of 6.4g of methanol dissolved in 50 moles of water2. If the density of the above solution at 25C is 1.03
ICE Princess25 [194]

Answer:

1. 0.22 mol/dm³

2. 0.23 mol/dm³

Explanation:

Molarity: This can be defined as the concentration of a substance  in mol per dm³

1.

M = n/v ...................... Equation 1

M = molarity of methanol, n = number of mole of methanol, v = volume of the solvent/water/solution.

<em>n = g/m.m</em>

<em>Where g = mass of methanol, m.m = molar mass of methanol.</em>

<em>g = 6.4 g, m.m = 32 g /mole.</em>

<em>n = 6.4/32 = 0.2 mole</em>

<em>and ,</em>

<em>v = m/d </em>

<em>Where m = mass of water, d = density of water</em>

<em>m = mass of 50 moles of water = 18×50 = 900 g.</em>

d = 1000 g/dm³.

v = 900/1000 = 0.9 dm³

Substituting the value of v and n into equation 1

M = 0.2/0.9

M = 0.22 mol/dm³

2.

M = n/v

v = volume of the solution

v = (mass of methanol + mass of water in the solution)/density of the solution

v = [(900+6.4)/1000]/1.03

v = 0.9064/1.03

v = 0.88 dm³

n = 0.2 mole

Therefore,

M = 0.2/0.88

M = 0.23 mol/dm³

3 0
3 years ago
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