Answer:
There is 54.29 % sample left after 12.6 days
Explanation:
Step 1: Data given
Half life time = 14.3 days
Time left = 12.6 days
Suppose the original amount is 100.00 grams
Step 2: Calculate the percentage left
X = 100 / 2^n
⇒ with X = The amount of sample after 12.6 days
⇒ with n = (time passed / half-life time) = (12.6/14.3)
X = 100 / 2^(12.6/14.3)
X = 54.29
There is 54.29 % sample left after 12.6 days
1 mol = 6.023x10^23 number of molecules (Avogadro's number)
1 : 6.023x10^23
X : 4.91x10^22
(6.023x10^23)X = 4.91x10^22
X = 4.91x10^22/6.023x10^23
X = 0.082 Moles
Mass of Ni = 0.015 mol Ni × (58.693 g Ni/1 mol Ni) = 0.88 g Ni
Answer:
64567000000 nanolitres
Explanation:
Base 10 decimal system: 1 milli = 1000000 nano
We simply multiply 64,567 millilitres by 1000000 to get our number in nanolitres:
64567(1000000) = 64567000000 nanolitres
