Answer:
The answer to the question is;
The concentration of the Solution #1 in terms of molarity is
0.16704X moles/litre.
Explanation:
Let the concentration of the stock solution be X moles/liter
Therefore, 83.52 ml of the stock solution contains
83.52×(X/1000) moles
Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of
500 ml of solution 1 contains 83.52×(X/1000) moles
Therefore 1000 ml or 1 litre contains 2×83.52×(X/1000) moles = 0.16704X moles/litre
The molarity of solution 1 is 0.16704X moles/litre.
The type of heat transfer you are referring to here is convection.
Answer:
is the solubility of
in 0.10 M
.
Explanation:
Concentration of calcium nitrate = ![[Ca(NO_3)_2]=0.10 M](https://tex.z-dn.net/?f=%5BCa%28NO_3%29_2%5D%3D0.10%20M)

![[Ca(NO_3)_2]=0.10 M=[Ca^{2+}]](https://tex.z-dn.net/?f=%5BCa%28NO_3%29_2%5D%3D0.10%20M%3D%5BCa%5E%7B2%2B%7D%5D)
Solubility product of the calcium fluoride = 
Solubility of calcium fluoride in calcium nitrate solution :

(0.10+S) (2S)
The expression of solubility is given by :
![K_{sp}=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)

Solving for S:

is the solubility of
in 0.10 M
.
Answer:
Group 1 elements become more reactive as we move down the group. These atoms are larger because they have more shells. ... The force of attraction between the nucleus and the electron is less than for smaller atoms, and the outer electron is lost more easily.
The answer is A
Hope this helps.