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Gnoma [55]
3 years ago
13

A flask at room temperature contains exactly equal amounts (in moles) of nitrogen and xenon. sort the conditions based on the ga

s described.
Chemistry
1 answer:
Anettt [7]3 years ago
4 0
A. Bin 3 
<span>B. Bin 1 Nitrogen has a smaller molecular weight and will effuse at a faster rate. </span>
<span>C. Bin 3. If the gases are at the same temperature, they have the same average kinetic energy. </span>
<span>D. Bin 1. Nitrogen has a greater average velocity since it is a lighter gas.</span>
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What is the correct iupac name of CH3-CH2-CH2CHO ?
kow [346]

the correct IUPAC name of the compound is 1-Butanal.

<h3>What are IUPAC names?</h3>

It is a system of naming organic compounds based on the longest carbon-to-carbon single bonds. It does not matter whether these longest chains are continuous or in a ring.

Thus, when the compound with the chemical formula, CH3-CH2-CH2CHO is considered. The longest carbon-to-carbon chain is 4. The 1st carbon carries a functional group known as an aldehyde.

Aldehydes are equipped with the carbonyl group and have the general formula R−CH=O. They are also sometimes referred to as formyl.

Aldehydes are named after their parent alkane chains with a slight modification. The 'e' is replaced with 'al'

The aldehyde in this case has four carbons. This means that the parent alkane is Butane. Therefore, the name of the compound will be 1-Butanal.

More on IUPAC names can be found here: brainly.com/question/16631447

#SPJ1

4 0
2 years ago
PLEASE HELP
neonofarm [45]

Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

5 0
3 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
1,5,25,125 what’s the pattern rule and extend by 3 more numbers
nika2105 [10]

For the first one the pattern is multiply the previous number by five as you see 1 x 5 = 5 and so on. To keep adding to it you would do

125 x 5 = 625     625 x 5 = 3125    3125 x 5 = 15625

Now for the second one the pattern is divide the previous number by three as you can see 2187 / 3 = 729 and so on. To keep going you would

81 / 3 = 27       27 / 3 = 9        9 / 3 = 3

I hope this helps you and if you have anymore questions i'll be  glad to answer them.



4 0
3 years ago
Describe the differences between polyp and medusa
stealth61 [152]
One difference is that some animals are polyp and some are medusa.


The other difference is that some animals have medusa in their life or polp in their life cycle.


Hope these two differences helps :D
5 0
3 years ago
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