Answer : 
is the oxidizing agent and Fe is the reducing agent.
Explanation :
Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.
Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.
The balanced redox reaction is :
The half oxidation-reduction reactions are:
Oxidation reaction : 
Reduction reaction : 
In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.
Oxidation reaction : 
Reduction reaction : 
In this reaction, 
is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 
is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.
Thus, is the oxidizing agent and Fe is the reducing agent.
Answer:
Explanation:
Alkyl groups are those which are derived from alkane by the removal of one hydrogen atom
For example ,methane CH4, and its corresponding alkyl groups is methyl -CH3
When new substance forms with different chemical and physical properties mostly a chemical change occurs.
hope it helps
When we balance this equation
SnO₂(s) + H₂(g) ⇄ Sn(s) + H₂O(g)
We will get
SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)
Solution:
Balancing this equation
SnO₂(s) + H₂(g) ⇄ Sn(s) + H₂O(g)
We have to balance the number of O
SnO₂(s) + H₂(g) ⇄ Sn(s) + 2H₂O(g)
We have to balance the number of H
SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)
We will get the balanced equation
SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [Sn(s) + H₂O(g)] / [SnO₂(s) + H₂(g)]
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Answer:
The answer to your question is:
Explanation:
1 mol = 6.022 x 10 ²³ atoms
755 moles = x
x = 755 x 6.022 x 10 ²³ / 1 = 4.54 x 10 ²⁶ atoms
