3 years ago

Given that g(x) =x^3 G(-x)

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

Answer:-x

Step-by-step explanation:

g(x)=x^3

g(-x)=(-x)^3=[(-1)^3]x=-1x

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Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.

Maslowich

Answer:

16 pi cubic units

Step-by-step explanation:

Given that a region is bounded by

$f(x)=√x, y=0, x=1, x=4$

And the region is rotated about x axis.

We can find that here radius would be y value and height would be dx

So volume would be as follows:

If f(x) is rotated about x axis volume

= $\pi \int\limits^b_a {y^2} \, dx \\=\pi \int\limits^4_1 {x} \, dx\\=\pi *x^2 ^4_1\\= \pi*16-1\\=15\pi$

cubic units.

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3 years ago

Alexander's dividing oranges into eighths he has 5 oranges.how many eights will be have

Veseljchak [2.6K]

Ther will be 40 eights. Hope this helps!

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3 years ago

Read 2 more answers

C=40.82 ft what is the radius an d diameter

vesna_86 [32]

The radius would be 40.82 divided 2 and that is 20.41 and the diameter would be 40.82 times 2 and that is 81.54

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3 years ago

Find the unit rate.

SIZIF [17.4K]

Answer:

152

Step-by-step explanation:

6840 divided by 45 is 152

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3 years ago

Solve the equation by completing the square. 2x-18x+58=0

lubasha [3.4K]

$x^{2} -18x+58=0$

We have got quadratic equation. We calculate it by using Δ.

$\Delta=(-18)^{2} -4*1*58=324-232=92>0$
$\sqrt{\Delta} = \sqrt{92} =2 \sqrt{23}$

$x_1= \frac{-b- \sqrt{\Delta} }{2a} = \frac{18-2 \sqrt{23} }{2} =9- \sqrt{23}$
∨
$x_2= \frac{-b+ \sqrt{\Delta} }{2a} = \frac{18+2 \sqrt{23} }{2} =9+ \sqrt{23}$

Hope it helps :)

5 0

3 years ago