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3 years ago

2x-1=y, 2y-4x=7 is the equation are parallel show break down

1 answer:

3 0

Y = 2x - 1...slope here is 2 and y int is -1

2y - 4x = 7
2y = 4x + 7
y = (4/2)x + 7/2
y = 2x + 7/2...slope here is 2 and y int is 7/2

When the slopes of the lines are the same, and the y intercepts different...this means they are parallel lines

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Write the five term sequence that would represent each recursive rule f(x) = f(x-1) -7; f(2) = 12

barxatty [35]

Answer:

Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

Solution:

Need to find the five terms of the sequence.

Given recursive rule is f(x) = f(x-1) -7

Substituting x = 2 , f(2) = f(2-1)-7

= f(2) = f(1) – 7 ------(1)

Also given that f(2) = 12.

On substituting the given value of f(2) in eq (1) we get

12 = f(1) – 7

f(1) = 12 + 7 = 19

Using given recursive rule and given value of f(2) calculating f(3)

Substituting x = 3 ,

f(3) = f(3-1) – 7

= f(2) – 7

= 12 – 7

= 5

Using given recursive rule and calculated value of f(3) calculating f(4)

Substituting x = 4,

f(4) = f(4-1) – 7

= f(3) – 7

= 5– 7

= -2

Using given recursive rule and calculated value of f(4) calculating f(5)

Substituting x = 5,

f(5) = f(5-1) – 7

= f(4) – 7

= -2– 7

= -9

Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

8 0

3 years ago

Plz help fast I’m taking a quiz

marta [7]

Y= -1 +1/1. I hope it’s correct if not u can use desmos

6 0

3 years ago

Read 2 more answers

Y=-x^2+6x-4 Find the Axis of Symmetry and the Vertex, Also solve the whole equation.

Inessa [10]

Answer:

1. Axis of symmetry: x = 3

2. Vertex: (3,5)

3. Solution of the equation:

x-intercepts:

$(3-\sqrt{5},0) \\\\(3+\sqrt{5},0)$

y-intercept: (0, -4)

Explanation:

1. Equation:

$y=-x^2+6x-4$

2. Axis of symmetry:

That is the equation of a parabola, whose standard form is:

$y=ax^2+bx+c$

Where:

$a=-1;b=6;c=-4$

The axis of symmetry is the vertical line with equation:

$x=-b/2a$

Substitute $a=-1,\text{ and }b=6$

$x=-6/[(2)(-1)]=-6/(-2)=3$

Thus, the axis of symmetry is:

$x=3$

3. Vertex

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

$y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5$

Therefore, the vertex is (3, 5)

4. Find the x-intercepts

The x-intercepts are the roots of the equation, which are the points wher y = 0.

$y=-x^2+6x-4=0$

Use the quadratic equation:

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}$

5. Find the y-intercept

The y-intercet is the value of y when x=0:

$y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4$

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4 years ago

Can y’all help me on question 19?!

m_a_m_a [10]

Answer: 178.31

Step-by-step explanation: subtract 574.54 by 396.23

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3 years ago

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Mathematical x4 - x2 ≥ 2x

kondaur [170]

X4-x2≥ 2x~~~2x≥ 2x True Because " _ " is the same thing with "=" ; and because 2x=2x then 2x≥ 2x ~~~~~~Have a nice day!!! ★★

4 0

3 years ago