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3 years ago

2x-1=y, 2y-4x=7 is the equation are parallel show break down

1 answer:

3 0

Y = 2x - 1...slope here is 2 and y int is -1

2y - 4x = 7
2y = 4x + 7
y = (4/2)x + 7/2
y = 2x + 7/2...slope here is 2 and y int is 7/2

When the slopes of the lines are the same, and the y intercepts different...this means they are parallel lines

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What is the measure of 3? triangle on right has angles labeled forty-four degrees, sixty-six degrees, and three.?

sveta [45]

[1] First, remember that the sum of the angles in a triangle must add up to 180*.

[2] We are told two of the angles, 44* and 66*, but we are missing the third.

[3] Combining [1] and [2], we know that 44* + 66* + ? = 180*. In other words,
110* + ? = 180*
so,
? = 70*

The missing angle 3 is equal to 70 degrees.

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3 years ago

PLEASE HELP!

agasfer [191]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the domain and range of the graph below in interval notation? If union is needed, use Capital U. If infinity is needed u

elena55 [62]

Answer:

DOMAIN: $(-\infty,1]\cup(2,\infty)$

RANGE: $(-\infty,\infty)$

Step-by-step explanation:

The domain of a graph is the span of x-values covered by the graph, while the range of a graph is the span of y-values covered by the graph.

DOMAIN:

From the graph, we can see that the x-values covers everything to the left of x=1. Then we stop and then continue beginning at x=2 all the way until positive infinity.

However, note that at x=1, the dot is a closed circle while at x=2, the dot is an open circle. Thus, we will include x=1 into our domain but not include x=2 into our domain.

So, our domain is all values greater than or less than 1, and all values greater than 2.

In interval notation, this is:

$(-\infty,1]\cup(2,\infty)$

We use brackets with the 1 because we include it in our domain and we use parentheses with the 2 since we do not.

RANGE:

Looking at the graph, it seems that all y-values are covered. The part of the graph on the left covers all y-values less than or equal to 3, while the part of the graph on the right covers all y-values greater than -1. Thus, all y-values are covered.

Our range is all real numbers.

In interval notation, this is:

$(-\infty,\infty)$

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3 years ago

Simplify the expression

Molodets [167]

Answer:

8x^8/3 y^4 - The first option

Step-by-step explanation:

The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.

This means that the expression is now:

8(x^2*4/3 y^3*4/3)

First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3

The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.

So now our expression is:

8(x^8/3 y^4)

Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:

8x^8/3 y^4 - The first option.

Hope this helped!

7 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$