First we need to know how many miles per hour they drove the first time. This would be found by division. 168/3.5=48
Then we need to add 5 miles per hour for the average.48+5= 53
Next we need to multiply 2 1/4 by the new miles per hour 53*2.25=119.25
After that we need to know how many miles they drove 119.25+168=287.25 miles.
Finally to get an improper fraction we need to change 287.25 miles to it.
We already have 1/4 for .25 so we multiply 287 by 4 and add it to the 1/4 we already have and it makes it out to be 1149/4
Hope this helps!
Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
Answer:
you have to do it yourself
The amount he pays is the number of shirts times 3 / 2 (or 1.5)
unless the equation is f=3/(2s) where the cost would then be the number of shirts times two, divided by three
